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anyanavicka [17]
3 years ago
10

The world's fastest humans can reach speeds of about 11 meters per second. In order to increase his gravitational potential ener

gy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb?
Physics
1 answer:
pychu [463]3 years ago
7 0

Answer:

6.16717 m

Explanation:

m = Mass of person

g = Acceleration due to gravity = 9.81 m/s²

h = Vertical height

v = Velocity of person = 11 m/s

According to the question

KE=PE\\\Rightarrow \dfrac{1}{2}mv^2=mgh\\\Rightarrow h=\dfrac{v^2}{2g}\\\Rightarrow h=\dfrac{11^2}{2\times 9.81}\\\Rightarrow h=6.16717\ m

The height the person would need to climb is 6.16717 m

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A car enters a level, unbanked semi-circular hairpin turn of 100 m radius at a speed of 28 m/s. The coefficient of friction betw
meriva

Answer:

As  28m/s = 28m/s

Explanation:

r = the radius of the curve

m =  the mass of the car

μ = the coefficient of kinetic friction

N = normal reaction

When rounding the curve, the centripetal acceleration is

a = \frac{v^{2}}{r}

therefore

\mu mg = m \frac{v^{2}}{r} \\\\ \mu =  \frac{v^{2}}{rg}

v = \sqrt{\mu rg}

\mu = \sqrt{0.8 \times 100\times9.8} \\\\= 28m/s

As  28m/s = 28m/s

8 0
4 years ago
Which are ways to improve the design of this experiment? Check all that apply.
forsale [732]
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6 0
4 years ago
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A GPS signal travels at the speed of light 300,000,000 m/s. If it takes .05s to reach a phone on the surface of the Earth, how f
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6 0
3 years ago
If 36 grams of water is to be heated from 24.0°C to 48°C to make a cup of tea, how much heat must be added? The specific heat of
Vinvika [58]

We will have the following:

\begin{gathered} Q=mc\Delta T\Rightarrow Q=(36)(4.18)(48-24) \\  \\ \Rightarrow Q=3611.52 \end{gathered}

So, the heat to add is 3611.52 Joules.

3 0
1 year ago
A 3 kilogram cat is resting on top of a bookshelf that is 1 meters high. What is the cat’s gravitational potential energy relati
AVprozaik [17]

We have: Gravitational Potential Energy (U) = mgh

Here, m = 3 Kg

g = 9.8 m/s²        [ constant value for earth system ]

h = 3 m


Substitute their values into the expression:

U = 3 × 9.8 × 3

U = 88.2 J


In short, Your Answer would be 88.2 Joules


6 0
3 years ago
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