I'll have to be honest with you. I've read both of those opinions several times, carefully, and it looks to me like both technicians are saying exactly the same thing.
Now, my knowledge of shims and camber is limited (to approximately zero), so all I can say to answer the question is this: If EITHER technician is correct, then they're BOTH correct.
Answer:
a. 3,392.7 N
b. 3,392.7 N
Explanation:
We are given the following information;
- Mass of the truck as 1052 kg
- initial speed as 0 m/s
- Final speed as 20.0 m/s
- Time taken as 6.20 s
#a. We are required to calculate the acceleration;
We need to know the formula of getting acceleration;
a = (v-u)/t
Where v is the final velocity, u is the initial velocity
Therefore;
a = (20 m/s - 0 m/s)/6.20s
= 3.225 m/s²
Thus, the average acceleration of the truck is 3.225 m/s²
#b. We are required to calculate the net force on the truck
We need to know that;
According to the second Newton's law of motion, F=ma
Where F is the net force, m is the mass and a is the acceleration.
Therefore;
Net force, F = mass × Acceleration
= 1052 kg × 3.225 m/s²
= 3,392.7 N
Thus, the net force on the truck is 3,392.7 N
The earth rotates (spins) at the same time as it orbits in a circular motion around the sun. fun fact : it takes 365 days to complete 1 orbit for 3 years and then 366 days for a leap year! you don't have to put that last part but maybe for some extra points you can!
750 divide 50 which is 15n
or it is 750 times 50 which is 37500n
