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N76 [4]
2 years ago
14

Problem: Asteroid Field.​

Physics
2 answers:
Vesna [10]2 years ago
6 0

Answer:

An asteroid is a minor planet of the inner Solar System. Historically, these terms have been applied to any astronomical object orbiting the Sun that did not resolve into a disc in a telescope and was not observed to have characteristics of an active comet such as a tail.

olchik [2.2K]2 years ago
6 0

Answer:

a place in our solar system where small bodies – mostly rocky and some metallic – orbit the sun. Sometimes scientists call these little worlds minor planets. One (Ceres) is even categorized as a dwarf planet. These objects move mostly between the orbits of our solar system’s 4th planet, Mars, and 5th planet, Jupiter. Astronomers once thought they were leftovers of a rocky planet that Jupiter’s gravity tore apart long ago. Now they think differently.

Explanation:

is the small thing that separated from the star and was near the planet Earth

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Answer:

C. displacement

Explanation:

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3 years ago
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Answer:

JA

Explanation:

s of time, (b) the velocity and acceleration at t = 2.0 s, (c) the time at which the position is a maximum, (d) the time at which the velocity is zero, and (e) the maximum position. Assume all variable and constants are in SI units.

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1. Which of the following is correct about the sampling distribution of the sample mean
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Answer:

In my opinion I think that the answer is C sorry If I get this wrong.

5 0
3 years ago
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
hodyreva [135]

Answer : The correct option is, (c) 3.7\times 10^2J/^oC

Explanation :

First we have to calculate the energy or heat.

Formula used :

E=V\times I\times t

where,

E = energy (in joules)

V = voltage (in volt)

I = current (in ampere)

t = time (in seconds)

Now put all the given values in the above formula, we get:

E=(3.6V)\times (2.6A)\times (350s)

E=3276J

Now we have to calculate the heat capacity of the calorimeter.

Formula used :

C=\frac{E}{\Delta T}=\frac{E}{T_{final}-T_{initial}}

where,

C = heat capacity of the calorimeter

T_{initial} = initial temperature = 20.3^oC

T_{final} = final temperature = 29.1^oC

Now put all the given values in this formula, we get:

C=\frac{3276J}{(29.1-20.3)^oC}

C=372.27J/^oC=3.7\times 10^2J/^oC

Therefore, the heat capacity of the calorimeter is, 3.7\times 10^2J/^oC

7 0
3 years ago
The fluid friction that opposes the motion of objects through air is known as what?
PSYCHO15rus [73]
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