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Alenkasestr [34]
2 years ago
6

Chemical equations should be balanced so that they demonstrate the law of conservation of mass. Which of the following statement

s about balanced chemical equations is correct?
A
The products must contain the same numbers and types of atoms as the reactants.

B
The products must contain the same arrangement of atoms as found in the reactants.

C
The products must contain the same numbers but not the same types of atoms as the reactants.

D
The products must contain the same types but not the same numbers of atoms as the reactants.
Physics
1 answer:
faust18 [17]2 years ago
7 0

Answer:

The products must contain the same numbers and types of atoms

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A horse runs a distance of 240 m in 20 s. Which of the following is a scalar quantity that can be determined from this
mariarad [96]

Explanation:

distance and time both are scaler quantity

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tu hermano y tu van al bosque a jugar basquetbol un rato, de regreso apuestan que el que llegue al final hará la cama del otro d
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3 years ago
Two equally charged, 2.098 g spheres are placed with 3.338 cm between their centers. When released, each begins to accelerate at
photoshop1234 [79]

Answer:

2.64\times 10^{-7} C

Explanation:

There are two spheres name 1 and 2 and they posses the same charge, which is +q.

And they have equal mass which is 2.098 g.

The distance between these two spheres is, r=3.338 cm.

And the acceleration of each sphere is, a=269.429 m/s^{2}.

Now the coulumbian force experience by 1 sphere due to 2 sphere,

F_{21} =\frac{q^{2} }{4\pi\epsilon_{0} r^{2}  }.

And also the newton force will occur due to this force,

F_{21}=ma.

Now equate the above two values of force will get,

\frac{q^{2} }{4\pi\epsilon_{0} r^{2}  } =ma

Further solve this,

q^{2}=ma4\pi  \epsilon_{0} r^{2}.

Substitute all the known variables in above equation,

q^{2}=(2.098\times 10^{-3} )(269.429)(4(3.14))(8.85\times 10^{-12})(3.338\times 10^{-2}).

q=2.64\times 10^{-7} C.

6 0
3 years ago
A and B start walking in the same direction at the same time around a circular park of diameter 4200 m. If A walks 10 m more tha
Liono4ka [1.6K]

Answer:

Va = 5000 m / 3600 s = 1.39 m/s

(Va - Vb) 60 = 10

Vb = Va - .167 = 1.22 m/s

(Va - Vb) T = 4200 Π      where T is time for A to complete 1 more lap

.17 T = 4200 Π

T = 24700 Π  time for A to again catch B

N = 1.39 * 24700 Answer:

Va = 5000 m / 3600 s = 1.39 m/s

(Va - Vb) 60 = 10

Vb = Va - .167 = 1.22 m/s

(Va - Vb) T = 4200 Π      where T is time for A to complete 1 more lap

.17 T = 4200 Π

T = 24700 Π  time for A to again catch B

N = 1.39 * 24700 Π / (4200 Π) = 8.2   laps

A will make 8 but not 9 rounds before catching B

6 0
2 years ago
A car accelerates from rest to 100 m/s in 20 s. What is its acceleration?
Dmitriy789 [7]
  • initial velocity=0m/s=u
  • Final velocity=v=100m/s
  • Time=t=20s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{100-0}{20}

\\ \sf\longmapsto Acceleration=\dfrac{100}{20}

\\ \sf\longmapsto Acceleration=5m/s^2

7 0
3 years ago
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