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Alenkasestr [34]
3 years ago
6

Chemical equations should be balanced so that they demonstrate the law of conservation of mass. Which of the following statement

s about balanced chemical equations is correct?
A
The products must contain the same numbers and types of atoms as the reactants.

B
The products must contain the same arrangement of atoms as found in the reactants.

C
The products must contain the same numbers but not the same types of atoms as the reactants.

D
The products must contain the same types but not the same numbers of atoms as the reactants.
Physics
1 answer:
faust18 [17]3 years ago
7 0

Answer:

The products must contain the same numbers and types of atoms

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A bowling ball (mass = 7.2 kg, radius = 0.11 m) and a billiard ball (mass = 0.38 kg, radius = 0.028 m) may each be treated as un
Semenov [28]

Answer:

Explanation:

Given that

Mass of bowling ball M1=7.2kg

The radius of bowling ball r1=0.11m

Mass of billiard ball M2=0.38kg

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Gravitational constant

G=6.67×10^-11Nm²/kg²

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r=r1+r2

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F=GM1M2/r²

F=6.67×10^-11×7.2×0.38/0.138²

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The force of attraction between the two balls is

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3 0
3 years ago
A vector in the xy plane has components -14.0 units in the x-direction and 30.0 units in the y-direction. What is the magnitude
OverLord2011 [107]

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

We would calculate the magnitude by applying pythagorean theorem:

\longrightarrow \sf{Magnitude= \sqrt{(-14)^2 } + 30^2}

\longrightarrow \sf{Magnitude = 33.12}

\longrightarrow \sf{The \:  vector \: is \: (- 14, 30)}

The angle between two vectors is given by the formula:

\sf{\longrightarrow \small  \cos \emptyset =  \dfrac{(a1b1 + a2b2)}{ \sqrt{(a1)^2 + (a2)^2√(b1)^2 + (b2)^2} } }

In two dimensional, the x axis of vector form is:

\small\sf{\longrightarrow (b1, b2) = (1, 0) }

\sf{\longrightarrow \small \cos \:  \emptyset =  \dfrac{(14 * 1 + 30 x 0)}{( \sqrt{(-14)^2 + (30)^2)(√(1)^2 + (0)^2)} } }

\small\longrightarrow \sf{ \dfrac{14}{33.12} }

\small\longrightarrow \sf{\emptyset  \:  = arcCos (\dfrac{ - 14}{33.12} )}

\small\longrightarrow \sf{\emptyset= 115^\circ}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\small\bm{The \: angle  \: between  \: the  \: vector \: }

\small\bm{and \: \: the \: \: positive \: \: x \: \: axis \: \: is \: \: \: 115^\circ .}

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alexgriva [62]
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boyakko [2]

Answer:

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