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ira [324]
4 years ago
13

The sensitivity of a measuring instrument is the value of the smallest quantity that can be read or estimated with it. What is t

he smallest part of a centimeter that can be read with the following?
(a) a meterstick with markings at each millimeter.

(b) a digital caliper with a four-digit display

I've got an answer for (a) which was 0.05cm, and tried the following for (b) but none was correct:

0.0001cm, 0.01mm, 0.002mm
Physics
1 answer:
nirvana33 [79]4 years ago
6 0

Answer:

The smallest part of a millimeter that can be read with a digital caliper with a four digit display is 0.02mm. Thus, it has to be converted to centimetre. So, divide by 10, we then have 0.02/10= *0.002cm* not mm.

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Explain why mess extinctions occur and why it make sense to measure geologic time between mass extinctions
Nastasia [14]
Mass extinction occur from natural disasters, such as a n asteroid hitting earth or a volcano errupting and spread ash everywhere.

It makes sense to measure geologic time between mass extinctions because after each mass extinction, there is almost no life left and the few left have to repopulate, which may lead way to new mutations and new varieties of plants and animals.
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3 0
3 years ago
A 55kg cart is pushed by a force of 225 n. what is the carts acceleration?
gayaneshka [121]
F=ma so a=F/m
a=225/55=4.09 m/sec^2
3 0
4 years ago
In the diagram, 91, 92, and q3 are in a straight line. Each of these particles has a charge of -2.35 x 10-6 C. Particles q₁ and
Strike441 [17]

The net force on particle q₃ is  6.2128125 N.

<h3>What is electrostatic force?</h3>

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/d²

where k = 9 x 10⁹ N.m²/C²

Given is the diagram in which each of the particles has a charge of -2.35 x 10⁻⁶ C. Particles q₁ and q₂ are separated by 0.100 m and particles q₂ and q₃ are separated by 0.100 m.

Force acting on q₃ due to q₁

F₃₁  = 9 x 10⁹ x (-2.35 x 10⁻⁶)²/(0.1)²

F₃₁ = 4.97025 N(in right direction)

Force acting on q₃ due to q₂

F₃₂ = 9 x 10⁹ x (-2.35 x 10⁻⁶)²/(0.1+0.1)²

F₃₂ = 1.2425 N (in right direction)

Net force acting on particle q₃ is

F₃ = F₃₁ +F₃₂

F₃ = 4.97025 N + 1.2425 N

F₃ = 6.2128125 N

Thus the net force on a charged particle is  6.2128125 N to the right.

Learn more about electrostatic force.

brainly.com/question/9774180

#SPJ1

3 0
2 years ago
Which statement describes the process of subduction? Convection currents pull a plate into the mantle. One plate slides beneath
mixas84 [53]

Answer:

  • Subduction is the geological process in which one plate moves under another due to gravitational pull. The regions where this process occurs called subduction zones.
  • A subduction is a tectonic plate which is made up of crust and upper layer of mantle. These two layers are called as lithosphere.
  • Example:  South America, central America and cascade volcanoes. In which the oceanic plate descends beneath a continental plate.  
7 0
3 years ago
Read 2 more answers
Suppose that a rectangular toroid has 1,500 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i
V125BC [204]

Answer:

Current in the toroid will be I=17.32\times 10^{-3}A

Explanation:

We have given number of winding in rectangular toroid N = 1500

Self inductance of toroid L = 0.06 H

Magnetic energy stored in toroid E=9\times 10^{-16}J

We have to find the current in the toroid

Magnetic energy stored is equal to E=\frac{1}{2}Li^2

9\times 10^{-6}=\frac{1}{2}\times 0.06\times I^2

I=17.32\times 10^{-3}A

So current in the toroid will be I=17.32\times 10^{-3}A

5 0
4 years ago
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