The sample used in this problem is classified as cluster.
<h3>How are samples classified?</h3>
Samples may be classified as:
- Convenient: Drawn from a conveniently available pool.
- Random: All the options into a hat and drawn some of them.
- Systematic: Every kth element is taken.
- Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
- Stratified: Also divides the population into groups. Then, a equal proportion of each group is surveyed.
For this problem, a group of schools is selected, and then the new program is applied to all students in these school, meaning that all elements in the cluster are surveyed, so cluster sampling is used.
More can be learned about classification of samples at brainly.com/question/25122507
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Answer:
30
Step-by-step explanation:
31-12=19
49-19=30
Good Luck?!
ANSWER
(2,2)
EXPLANATION
Since f(x) and its inverse function are symmetric about the line y=x, if (a,b) lies on the graph of f, then (b,a) must lie on f inverse.
The point (2,2) lies on f and the same time on f inverse.
The solution is a point that satisfies both equations.
Hence the correct choice is:
(2,2)
A (5, 4) and B( 5, -2) is 6 units
E(-2, -1) and F(-2, -5) is 4 units
G(3, -5) and H(6, -5) is 3 units
C(-4, 1) and D(1, 1) is 5 units
Step-by-step answer:
Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals
Ra = 2Fcos(a) ..............................(1)
Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals
Rb = 2Fcos(b)..............................(2)
We are given that
Ra = 2Rb ....................................(3)
Substitute (1) & (2) in (3) gives
2Fcos(a) = 2(2Fcos(b))
Expand
2Fcos(a) = 4Fcos(b)
Simplify
cos(a) = 2 cos(b) QED
Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.
Have a nice day!
