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storchak [24]
3 years ago
12

If you invested $100 at an interest rate of 5% per year compounded quarterly, how much will the investment be worth at the end o

f two years? *
50 points
Mathematics
1 answer:
mojhsa [17]3 years ago
5 0

Answer: the investment would be

$110.45

Step-by-step explanation:

Initial amount deposited into the account is $100 This means that the principal is

P = 100

It was compounded quarterly. This means that it was compounded 4 times in a year. So

n = 4

The rate at which the principal was compounded is 5%. So

r = 5/100 = 0.05

It was compounded for 2 years. So

t = 2

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. Therefore

A = 100 (1+0.05/4)^4×2

A = 100 (1.0125)^8

A = $110.45

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If
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Answer: -104

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4 0
2 years ago
Find the area of the region in two ways. a. Using integration with respect to x. b. Using geometry. 9-x
Natali [406]

Answer: hello your question is incomplete attached below is the complete question

answer :

a)   \int\limits^3_0 {(10-x)-(x+4)} \, dx     ( option D )

b) A =  1/2 (6)(3)   ( option B )

c) Area of shaded region = 9

Step-by-step explanation:

<u>a) Using integration with respect to x </u>

Area =   \int\limits^7_4 {(y-4)} \, dy + \int\limits^a_7 {(10-y)} \, dy         ( note a = 10 )

          = y^2/2 - 4y |⁷₄  + 10y - y^2/2 |¹⁰₇

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hence the best integral from the options attached is option D

\int\limits^3_0 {(10-x)-(x+4)} \, dx

= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀

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<u>b) Using Geometry </u>

Area = 1/2 * base * height

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3 years ago
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