Answer:
A regular 12-oz beer is about 5% alcohol. This works out to about 14.03 grams of alcohol per beer. If the driver drank two beers, how many grams of alcohol did he consume? <u>28.06 grams</u>
The driver weighs about 160 lbs. What is his body weight in kg? What is his body volume in mL? (1 lb = 0.45 kg) (1 kg = 1000 mL) <u>72.57 kg/72,560 mL</u>
For most males, 68 percent of the body is water. What is the volume of water in the driver’s body in mL? <u>49,350 mL</u>
Use the above information to calculate BAC. <u>0.0569%</u>
The measured BAC was 0.12%. Was the driver telling the truth about how much he drank? Calculate the difference between the two BAC percentages. <u>No. 0.0569% is different.</u>
If the driver had really consumed only two beers, would he have been arrested for DUI? Explain. <u>The driver would not have been arrested if he only had two beers. He more or less had more than two beers in his car when the police checked his car.</u>
Step-by-step explanation:
the underlined areas are your answers.
Answer:
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Answer:
9lb chocolate candies
6lb sugar candies
Step-by-step explanation:
Yes, I also happen to go to RSM. (6b)
Equation: 7x+2(15-x)=5*15
Solve:
7x+(2)(15)+(2)(−x)=(5)(15)
7x+30+(−2x)=75
(7x+(−2x))+(30)=75
5x+30=75
5x=45
x=9lb chocolate candies
Now, calculate the sugar candies.
15-9=6lb sugar candies
