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olga55 [171]
3 years ago
11

Explorer 35's orbit measured 11,400 kilometers across its long dimension. What was the orbit's semimajor axis in kilometers?a. 5

,700 kmb. 9,600 kmc. 11,400 kmd. 22,800 km
Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

option (a)

Step-by-step explanation:

Length of long dimension = 11400 km

It means it is the length of major axis.

So, the length of semi major axis = 11400 / 2 = 5700 km

Thus, the length of semi major axis is 5700 km.

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2. Ravi purchased an old house for Rs. 76.5000 and
lorasvet [3.4K]

Answer:

Rs. 924000.

Step-by-step explanation:

Cost of  house = 765000

Additional money spent on it = 115000

Total cost incurred by Ravi = 765000 + 115000 = 880000

Gain  = 5% of total cost

gain in Rs = 5/100 * 880000 = Rs. 44000

Total selling price of house = total cost incurred + profit = 880000+ 44000

Total selling price of house = Rs. 924000

Thus, Ravi got  Rs. 924000.

3 0
4 years ago
Please help me with this question!
nika2105 [10]

Answer:

3

Step-by-step explanation:

3 0
3 years ago
Write and solve an equation to answer the question. after earning interest, the balance of a checking account is $560. the new b
nikitadnepr [17]
2.33 is the aprox number we start off with. if we got to find the original, we divide 560 by (7/3).
after we estimate the divisior we get 240. 560 - 240 gives us 320.
the answer could be 320.
7 0
3 years ago
The Genetics & IVF Institute conducted a clinical trial of the YSORT method designed to increase the probability of conceivi
Reika [66]

Answer: The test statistic needed to test this claim= 10.92

Step-by-step explanation:

We know that the probability of giving birth to a boy : p= 0.5

i..e The population proportion of giving birth to a boy =  0.5

As per given , we have

Null hypothesis : H_0: p\leq0.5

Alternative hypothesis :  H_a: p>0.5

Since H_a is right-tailed , so the hypothesis test is a right-tailed z-test.

Also, it is given that , the sample size : n= 291

Sample proportion: \hat{p}=\dfrac{239}{291}\approx0.82

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} , where n is sample size ,  \hat{p} is sample proportion and p is the population proportion.

\Rightarrow\ z=\dfrac{0.82-0.5}{\sqrt{\dfrac{0.5(1-0.5)}{291}}}\approx10.92

i.e. the test statistic needed to test this claim= 10.92

Critical value ( one-tailed) for  0.01 significance level = z_{0.01}=2.326

Decision : Since Test statistic value (10.92)> Critical value (2.326), so we reject the null hypothesis .

[When test statistic value is greater than the critical value , then we reject the null hypothesis.]

Thus , we concluded that we have enough evidence at 0.01 significance level to support the claim that the YSORT method is effective in increasing the likelihood that a baby will be a boy.

7 0
3 years ago
Horizontal asymptote
vodomira [7]

Answer:

H.A.=4

Step-by-step explanation:

If the bottom equation is factored, you get (x+1)(x-4)

If the V.A. is -1 ( gotten by putting [x+1] equal to zero I'm guessing) then the H.A. can be gotten by putting (x-4) equal to zero.

Also, I graphed it.

6 0
3 years ago
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