3 years ago

What are the dimensions of a rectangle with an area of 304 and a perimeter of 70?

1 answer:

5 0

Area = 304 cm^2
perimeter = 70
perimeter = 2(l+w)
70 = 2(l+w)
70/2 = l+w
35 = l+w
Now suppose the length would be = x
width would be= 35-x
NOW Area = l*w
304 = x * (35-x)
304 = 35x -x^2
x^2-35x+304 = 0
use quadratic formula to solve next ok

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