I need help with 7 please
1 answer:
First put the equation in y- intercept form y= mx + b
1/3x + y = 2
y = -1/3x + 2
From this form, we can see that the y-intercept is 2. So that point on the graph is (0, 2). Now let's find another point. Set x equal to 3. So
y = -1/3 (3) +2
y = -1 + 2 = 1
So our point is (3, 1)
Use these 2 points to graph the equation. To find other points you could use the slope to find them. The slope is represented by x in the equation (-1/3). Or you could set another x point and solve for y again. See the pic for the graph.
1/3x + y = 2
y = -1/3x + 2
From this form, we can see that the y-intercept is 2. So that point on the graph is (0, 2). Now let's find another point. Set x equal to 3. So
y = -1/3 (3) +2
y = -1 + 2 = 1
So our point is (3, 1)
Use these 2 points to graph the equation. To find other points you could use the slope to find them. The slope is represented by x in the equation (-1/3). Or you could set another x point and solve for y again. See the pic for the graph.
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Step-by-step explanation:
taking common (a-b)
so we get the answer
