I need help with 7 please
1 answer:
First put the equation in y- intercept form y= mx + b
1/3x + y = 2
y = -1/3x + 2
From this form, we can see that the y-intercept is 2. So that point on the graph is (0, 2). Now let's find another point. Set x equal to 3. So
y = -1/3 (3) +2
y = -1 + 2 = 1
So our point is (3, 1)
Use these 2 points to graph the equation. To find other points you could use the slope to find them. The slope is represented by x in the equation (-1/3). Or you could set another x point and solve for y again. See the pic for the graph.
1/3x + y = 2
y = -1/3x + 2
From this form, we can see that the y-intercept is 2. So that point on the graph is (0, 2). Now let's find another point. Set x equal to 3. So
y = -1/3 (3) +2
y = -1 + 2 = 1
So our point is (3, 1)
Use these 2 points to graph the equation. To find other points you could use the slope to find them. The slope is represented by x in the equation (-1/3). Or you could set another x point and solve for y again. See the pic for the graph.
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The values of x and y are 8 and 0 respectively.
<em><u>Explanation</u></em>
As 'p' is located at (0,0) and 'r' is located at (-12,0) , that means both 'p' and 'r' are on the x-axis. So point 'q' will be also on the x-axis , and 'q' is located at (x,y)
So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)
Now, using the Distance formula, length of 'pq'
and length of 'pr'
Given that, pq : pr =2/3
So....
Thus, the values of x and y are 8 and 0 respectively.