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3 years ago

6

A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a consta

nt force (in contrast to the constant power in Part A). If such a sports car went from zero to 31.0 in time 1.40 , how long would it take to go from zero to 62.0 ?

1 answer:

bonufazy [111]3 years ago

8 0

Answer:

acceleration = 22.14 m/s²

time = 2.80 s

Explanation:

given data

initial velocity = 31.0

final velocity =

time = 1.40

solution

we get here acceleration that is

acceleration = $\frac{v(final) - v(initial)}{t}$ ...............1

acceleration = $\frac{31-0}{1.40}$

acceleration = 22.14 m/s²

and

by kinematic equation of motion

v = u +at .........2

t = $\frac{62-0}{22.14}$

time = 2.80 s

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