Question

A cannon is shot at a 30 degree angle above the horizontal with a velocity of 240 m/s. What is the range of this shot?

Answer 1

Answer:

Range, R = 5090.1 meters

Explanation:

It is given that,

Velocity of cannon, v = 240 m/s

A cannon is shot at a 30 degree angle above the horizontal. The range of this shot is given by the formula as follows :

$R=\dfrac{v^2\ sin2\theta}{g}$

g = acceleration due to gravity

$R=\dfrac{(240\ m/s)^2\ sin2(30)}{9.8\ m/s^2}$

R = 5090.1 meters

So, the range of this shot is 5090.1 meters. Hence, this is the required solution.