Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.
<h3>What centers of distribution should be used?</h3>
The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.
The data is said to be symmetric when the mean and median are equal or very close.
Bakery A mean:
= (45 + 52 + 51 48 + 61 + 34 + 55 46) / 8
= 49
Bakery A median is 49.5
Bakery B mean:
= (48 42 + 25 45 + 57 + 10 + 43 + 46 ) / 8
= 39.5
Bakery B median is 44.
This shows that Bakery A data is symmetric so the best center of distribution to use is mean.
Bakery B is not symmetric so the center of distribution to use is median.
Find out more on symmetric data at brainly.com/question/7130507
#SPJ1
Answer:
JT=19
Step-by-step explanation:
3x+6+3x+7=37
6x+6+7=37
6x+13=37
-13 -13
6x=24
6x/6=24/6
x=4
3x+7
3(4)+7
12+7
JT=19
First, you have to simplify the equation:
y+3 = 3(x+5)
y+3=3x+15
So you multiply what’s inside the brackets (x+5) by the factor (3). So 3•x=3x, 3•5=15.
Then you rearrange the equation as necessary to convert it into standard form, which is Ax + By = C
Answer:
It's asking you to find the inputs of the function.
Step-by-step explanation:
Basically, when you input something, you replace "x" in the equation with the number you want to input. For example, if I had the equation: 5x/6+5, then I wanted to input "5", then 5 would replace x in the equation, making 5(5)/6+5. The output they are giving you is simply evaluating the equation that you used to input x, so basically in the case I gave you, the output would be 5(5)/6+5, or 25/6+5, and 55/6. Using the outputs, they want you to find the inputs.
