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Ludmilka [50]
3 years ago
10

What two numbers add up to -14 and multiply out to -240

Mathematics
2 answers:
sashaice [31]3 years ago
8 0

Answer:

10-24

Step-by-step explanation:

wlad13 [49]3 years ago
4 0
So x+y=-14
xy=-240

x+y=-14
subtract y from both sides
x=-14-y
subsitute for x in second equation
(-14-y)y=-240
multiply
-y^2-14y=-240
add y^2+14y to both sides
0=y^2+14y-240
use quadratic equation to solve which is \frac{-b+/- \sqrt{b^2-4ac} }{2a} =x if you have ax^2+bx+c so

a=1
b=14
c=-240
subsitute and get \frac{-14+/- \sqrt{14^2-4(1)(-240)} }{2(1)} =10 or -24  (+/- means that there are 2 equations exg 2+/-8=2+8 and 2-8)

the numbers are 10 and -24
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You could simplify this work by factoring "3" out of all four terms, as follows:

3(x^2 + 2x - 3) =3(0) = 0

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Answer:

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Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

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For real repeated roots the solution is given by:

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As you can see, is the same solution provided by the problem.

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