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3 years ago

7

Elizabeth is planning to build an open top container for her vegetable garden. How many square inches of wood does she need to c

reate the bed? Enter your answer in the box. Length=24in Height=15in Width=54in
______in2

1 answer:

Vitek1552 [10]3 years ago

3 0

The correct answer is 3636in<span />

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A baker buys 7 cups of strawberries to make a cheesecake and 8 equal batches of muffins. The baker uses 3 cups of strawberries t

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1/2 because the baker has 4 cups of strawberries after they make the cheesecake and the 4 cups divided between the 8 batches would equal 1/2 cup of strawberries in each batch

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3 years ago

How many ways are

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3 years ago

Write the equation of<br> the line that passes<br> through (2,-4) &<br> has a slope of -1.

zzz [600]

Answer:

y= -1x-6

Step-by-step explanation:

The equation would be y=mx+b

M= slope, and B=y-intercept

If you look at a graph and use the slope to get to the Y-intercept you'll see that it is -6, and so you would just plug that into the equation along with the slope :)

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3 years ago

Above is a table with missing terms. Come up with a possible common difference that makes sense and list the missing terms.

Rina8888 [55]

Answer:

common ratio:2 2. 18 3.36 4.72 equation: 4.5( $2^x$ )

Step-by-step explanation:

144=2*2*2*2*3*3 9=3*3

the common ratio would be 2

2. 9*2=18

3. 18*2=36

4. 36*2=72

(check) 72*2=144

0. 9/2=4.5

equation: 4.5( $2^x$ )

7 0

3 years ago

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

3 years ago