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irga5000 [103]
3 years ago
7

Need help on this please

Mathematics
2 answers:
uranmaximum [27]3 years ago
4 0
7/8% is .875 as a decimal.
kati45 [8]3 years ago
4 0
7/8 is 0.00875 is your answer
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What is the solution -10 = 2a - 4
Simora [160]

Add 4 to both sides

-10 + 4 = 2a

Simplify -10 + 4 to -6

-6 = 2a

Divide both sides by 2

-6/2 = a

Simplify 6/2 to 3

-3 = a

Switch sides

<u>a = -3</u>

6 0
3 years ago
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What is 49,736 to the nearest thousands?
brilliants [131]
50,000
Since 736 is \geq 500, we round it off to 50 000 instead of 49000. 
5 0
3 years ago
3/4 x 1/8 in simples form
Zielflug [23.3K]

Answer:

3/32

Step-by-step explanation:

To get this answer, multiply the numerators together and the denominators together

3x1=3

4x8=32

3/32

5 0
3 years ago
( − 6 u 9 − 14 u 3 ) + ( − 13 u + 2 u 9 )
OverLord2011 [107]

Answer:=−91u

Step-by-step explanation:

5 0
2 years ago
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Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

5 0
3 years ago
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