Answer: 0.0475
Step-by-step explanation:
Let x = random variable that represents the number of a particular type of bacteria in samples of 1 milliliter (ml) of drinking water, such that X is normally distributed.
Given: 
The probability that a given 1-ml will contain more than 100 bacteria will be:
![P(X>100)=P(\dfrac{X-\mu}{\sigma}>\dfrac{100-85}{9})\\\\=P(Z>1.67)\ \ \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Zz)=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E100%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B100-85%7D%7B9%7D%29%5C%5C%5C%5C%3DP%28Z%3E1.67%29%5C%20%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C1.67%29%5C%20%5C%20%5C%20%5BP%28Z%3Ez%29%3D1-P%28Z%3Cz%29%5D%5C%5C%5C%5C%3D1-%200.9525%3D0.0475)
∴The probability that a given 1-ml will contain more than 100 bacteria
0.0475.
The distance between the helicopter and the first home is 369. 87 m
<h3>How to solve the distance using the angle of depression?</h3>
The distance between the helicopter and the first home can be found using sine law,
Hence,
180 - 72 - 49 = 59 degrees.
Therefore,
420 / sin 59 = A / sin 49°
where
- A = distance form the first home to the helicopter.
cross multiply
420 sin 49 = A sin 59°
A = 420 sin 49 / sin 59
A = 316.978023694 / 0.8571673007
A = 369.869339199
A = 369. 87 m
Therefore, the distance between the helicopter and the first home is 369. 87 m
learn more on angle of depression here: brainly.com/question/1976859
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Well if finding X you get 4,-7 when you simplify the whole equation you get that as well.
Answer:d=5/3x
Step-by-step explanation:
Let's solve for d.
(2/3x)(d)=10/9
Step 1: Divide both sides by (2x)/3.
2/3dx / 2x/3=10/9 / 2x/3
d=5/3x
