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Lana71 [14]
3 years ago
11

Ameeta finished 12 math problems. David finished 3 times as many. How many more math problems did David finish than Ameeta?

Mathematics
1 answer:
Volgvan3 years ago
8 0
  • Answer:
  • david finished 24 problems more than ameetha
  • Step-by-step explanation:
  • <em>problems finished by ameetha = 12 problems</em>
  • <em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36</em>
  • <em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =</em>
  • <em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =36-12= 24 </em>
  • <em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =36-12= 24 so David finished 24 problems more than ameetha</em>
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Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?
Alexeev081 [22]
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4 years ago
Find an ordered pair , x y that is a solution to the equation. 3x-y=1
NemiM [27]

Answer:

2,5

Step-by-step explanation:

2,5 is just one of the many solutions to this problem. you can just take a random number for x, for example 2. your equation will look like this 3(2)-y=1. now you just solve for y. 3x2=6. 6-1=5. so y=5.

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3 years ago
A triangle has three different integer side lengths and a perimeter of 20 units. What is the max length of any one side?
Troyanec [42]
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3 0
3 years ago
20 points repost because no one answered. Geomertry question
aniked [119]

Answer:

x=2.25

Step-by-step explanation:

ΔABC and ΔADE are similar.

∴ sides are proportional.

\frac{5}{1} =\frac{x+9}{x} \\5=\frac{x}{x} +\frac{9}{x} \\5=1+\frac{9}{x}\\\frac{9}{x}=5-1\\\frac{9}{x}=4\\x=\frac{9}{4}=2.25

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