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3 years ago

What is the end behavior of the function f(x)=2e^x? Select the two correct answers.

Mathematics

1 answer:

deff fn [24]3 years ago

7 0

Answer:

As x approaches infinity, f(x) approaches infinity.

As x approaches negative infinity, f(x) approaches 0.

Step-by-step explanation:

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Vicki ate 15 cookies last week. If she ate 5 cookies Friday, what fraction of the week's cookies did she eat Friday? What fracti

Anika [276]

Vicki ate 5/20 cookies on Friday and 15/20 last week

7 0

2 years ago

Find the quadratic function y=f(x) whose graph has a vertex (−3,4) and passes through the point (−7,0). Write the function

olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola. The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front. So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex: x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

$a=-\frac{1}{4}$

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

$y=-\frac{1}{4}(x+3)^2+4$

Now we will FOIL out what's inside the parenthesis to get

$y=-\frac{1}{4}(x^2+6x+9)+4$

Simplify by distributing the -1/4 into the parenthesis:

$y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4$

Combine like terms to get

$y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}$

And there you go!

5 0

3 years ago

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

7 0

3 years ago

Dominic is deciding if he should become a member of his local ice rink. The $144 annual membership fee at the ice rink includes

Alenkasestr [34]

Answer:

1. members = $ 160 , non members = $ 80

2. members = $ 168 , non members = $ 120

Step-by-step explanation:

For members

Annual membership = $ 144

rent per visit charges = $ 4

For Non members

parking charges = $ 5

admission charges = $ 11

rent per visit = $ 4

(1) for 4 visits

Members pay = $ 144 + 4 x $ 4 = $ 160

Non members pay = 4 x $ 11 + 4 x $ 5 + 4 x $ 4 = $ 80

So, non member ship is better.

(2) for 6 visits

Members pay = $ 144 + 6 x $ 4 = $ 168

Non members pay = 6 x $ 11 + 6 x $ 5 + 6 x $ 4 = $ 120

So, non member ship is better.

6 0

3 years ago

The circle below is centered at (3, 1) and has a radius of 2. What is its<br> equation?

MissTica

Answer:

( x-3) ^2 + ( y-1) ^2 = 4

Step-by-step explanation:

The equation for a circle is given by

( x-h)^2 + ( y-k) ^2 = r^2 where (h,k) is the center and r is the radius

( x-3) ^2 + ( y-1) ^2 = 2^2

( x-3) ^2 + ( y-1) ^2 = 4

5 0

2 years ago