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slega [8]
3 years ago
11

An out-of-control train is racing toward the Metropolis terminal train station - only Superman can help. The train has a mass of

75000 kg, and Superman has a mass of 115 kg. If the train has a velocity of 35 m/s, how fast does Superman have to fly in the opposite direction to stop it in a totally inelastic steel-Man-of-Steel collision?
Physics
1 answer:
Finger [1]3 years ago
8 0

Answer:

22826.09 m/s

Explanation:

From the law of conservation of momentum,

Sum of momentum before collision = sum of momentum after collision.

For an inelastic collision, the train and the superman have a common velocity

Note: For the superman to stop the train in an opposite direction, the common velocity after collision is zero, and such the total momentum after collision is zero

Therefore,

MU + mv = 0

MU = - mu............................................ Equation 1

Making u the subject of the equation

u = -MU/m......................................... Equation 2

Where M = mass of the train, U = initial velocity of the train, m = mass of the super man, u = initial velocity of the superman.

Given: M = 75000 kg, U = 35 m/s, m = 115 kg.

u = -(75000×35/115)

u = -22826.09 m/s

Note: The velocity is negative because the direction of the superman is opposite the direction of the train.

Hence the superman have to fly 22826.09 m/s in the opposite direction

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Mademuasel [1]
What you are describing is Amplitude.
6 0
2 years ago
If a skydiver weighs 800 N, what would air resistance be when he is at terminal velocity?
serg [7]
We call "terminal velocity" the constant speed of a falling body
when it is no longer accelerating.

We know that if a body is not accelerating, then the net force
on it is zero.

From the question, we know that the downward force of gravity
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If the 800 N downward plus the air resistance upward add up
to zero, then the air resistance upward must also be 800 N.
5 0
3 years ago
Read 2 more answers
Check my work. thank u sm!​
Mashcka [7]

Answer:

its correct no need to change anything :))

7 0
3 years ago
A student was asked to push a large box down the hallway about 35 meters. the task took the student five minutes and a force of
zaharov [31]
Rate of work or Power done by the student can be computed with below formulas.
1. Formula for Work
Work = Force x distance
Force or F = Force applied to the object 
distance or d = displacement

2. Formula for Power
P = Work done / Time it was done or completed

Substituting the values we have,
Work or Work done = 150 N x 35 meters = 5250 J (unit of work).

Lastly computing for the rate we have,
Power or rate of work = 5250 J / 300 seconds (or 5 min) = 17.5 Joule/S or Watts

Answer is 17.5 watts

5 0
3 years ago
An object is dropped from an airplane and takes 72 seconds to hit the ground. What is the magnitude of its VF Y ?
Dafna1 [17]

The final vertical velocity of the object is 705.6 m

Explanation:

Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of

g=9.8 m/s^2

towards the ground due to gravity.

Therefore, we can use the following suvat equation:

v=u+at

where

v is the final vertical velocity

u is the initial vertical velocity

a=g is the acceleration

t is the time

Since the object is dropped,

u = 0

Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:

v=0+(9.8)(72)=705.6 m/s

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

3 0
2 years ago
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