1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yakvenalex [24]
3 years ago
14

The data indicate the populations of mammals in the Florida Everglades in different years over the past two decades. The Burmese

python, a non-native species, was introduced to Florida as an exotic pet. After Hurricane Andrew hit Florida in 1992, many pet owners lost track of their non-native snakes. The biodiversity of the Everglades has decreased since then. According to the data, what hypothesis is best supported with regard to Burmese pythons and Florida Everglade biodiversity? A) Burmese pythons are omnivorous and have decreased all populations of mammals. B) Burmese pythons compete with the white-tailed deer most directly for food sources. C) Burmese pythons lack natural predators and can utilize a wide variety of food sources in the Everglades. D) Burmese pythons carry diseases and parasites that directly impact the mammal populations of the Everglades.
Physics
1 answer:
soldier1979 [14.2K]3 years ago
8 0

Answer:

C) Burmese pythons lack natural predators and can utilize a wide variety of food sources in the Everglades.

Explanation:

Due to it being an invasive specie (naturally found in South Asia), and also one of the five largest species of snakes in the world, the Burmese pythons lack natural predators in this new territories.

The Burmese viper is also an opportunistic hunter and would eat anything it can overpower, it easily made a wide range of food varieties in these swamps.

You might be interested in
A cardboard box sits on top of a concrete sidewalk where the coefficient of friction between the surfaces is 0.3. The mass of th
blagie [28]
Hope these r correct:
Normal Force≈ 68.5
Frictional Force≈ 20.5
Accel. ≈ 58.5

These are rounded
6 0
2 years ago
5. It took 500 newtons of force to push a car 40 meters. How<br> much work was done?
Hunter-Best [27]

Answer:

Explanation:

work done=force * displacement

=500 N * 40 m

=2000 joule

6 0
3 years ago
1. Is this circuit SERIES or PARALLEL?
Setler79 [48]

Answer:

Series

Explanation:

Because I listen to my science teacher

3 0
3 years ago
Two guitarists attempt to play the same note of wavelength 6.50 cm at the same time, but one of the instruments is slightly out
PolarNik [594]

Answer:

The two value of the wavelength for the out of tune guitar is  

\lambda _2 = (6.48,6.52) \ cm

Explanation:

From the question we are told that

     The wavelength of the note is \lambda  =  6.50 \ cm = 0.065 \ m

     The difference in beat frequency is \Delta  f = 17.0 \ Hz

     

Generally the frequency of the note played by the guitar that is in tune is  

        f_1 = \frac{v_s}{\lambda}

Where v_s is the speed of sound with a constant value v_s  =  343 \ m/s

       f_1 = \frac{343}{0.0065}

      f_1 = 5276.9 \ Hz

The difference in beat is mathematically represented as

       \Delta  f =  |f_1 - f_2|

Where f_2 is the frequency of the sound from the out of tune guitar

     f_2 =f_1  \pm \Delta f

substituting values

      f_2 =f_1 + \Delta f

      f_2 = 5276.9 + 17.0  

     f_2 = 5293.9 \ Hz

The wavelength for this frequency is

      \lambda_2 = \frac{343 }{5293.9}

     \lambda_2 = 0.0648 \ m

    \lambda_2 = 6.48 \ cm

For the second value of the second frequency

     f_2 =  f_1 - \Delta f

     f_2 = 5276.9 -17

      f_2 = 5259.9 Hz

The wavelength for this frequency is

   \lambda _2 = \frac{343}{5259.9}

   \lambda _2 = 0.0652 \ m

   \lambda _2 = 6.52 \ cm

8 0
3 years ago
A firecracker in a coconut blows the coconut into three pieces. Two pieces of equal mass fly off south and west, perpendicular t
Lisa [10]

Explanation:

Let us assume that piece 1 is m_{1} is facing west side. And, piece 2 is m_{2} facing south side.

Let m_{1} \text{and} m_{2} = m and m_{3} = 2m. Hence,

        2mv_{3y} = m(21)

          v_{3y} = \frac{21}{2}

                     = 10.5 m/s

2mv_{3x} = m(21)

          v_{3x} = \frac{21}{2}

                     = 10.5 m/s

  v_{3} = \sqrt{v^{2}_{3x} + v^{2}_{3y}}

              = \sqrt{(10.5)^{2} + (10.5)^{2}}

              = 14.84 m/s

or,          = 15 m/s

Hence, the speed of the third piece is 15 m/s.

Now, we will find the angle as follows.

          \theta = tan^{-1} (\frac{v_{3y}}{v_{3x}})

                      = tan^{-1}(\frac{10.5}{10.5})

                      = tan^{-1} (45^{o})

                      = 45^{o}

Therefore, the direction of the third piece (degrees north of east) is north of east.

5 0
4 years ago
Other questions:
  • A plucked violin string carries a traveling wave given by the equation f(x,t)=asin[b(x−ct)+ϕi], with a = 0.00580 m , b = 33.05 m
    10·2 answers
  • The various types of electromagnetic radiation are distinguished from each other by their
    15·1 answer
  • Gauss’s law applies to:_____________
    6·1 answer
  • Large wind turbines with a power capacity of 8 MW and blade span diameters of over 160 m are available for electric power genera
    12·2 answers
  • What are physical characteristics of roundworms? Hint: There are two stages of reproduction.
    13·1 answer
  • An ideal gas is compressed in a well-insulated chamber using a well-insulated piston. This process is
    15·1 answer
  • How many types of waves are there? What are the names?
    12·1 answer
  • Class these in chronological order of appearance in the Universe: hydrogen atom---proton---hydrogen nucleus
    12·1 answer
  • 4 pleasee i have to submit in 10 minutes
    7·1 answer
  • On average, how many lunar eclipses are there every year?.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!