1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yakvenalex [24]
3 years ago
14

The data indicate the populations of mammals in the Florida Everglades in different years over the past two decades. The Burmese

python, a non-native species, was introduced to Florida as an exotic pet. After Hurricane Andrew hit Florida in 1992, many pet owners lost track of their non-native snakes. The biodiversity of the Everglades has decreased since then. According to the data, what hypothesis is best supported with regard to Burmese pythons and Florida Everglade biodiversity? A) Burmese pythons are omnivorous and have decreased all populations of mammals. B) Burmese pythons compete with the white-tailed deer most directly for food sources. C) Burmese pythons lack natural predators and can utilize a wide variety of food sources in the Everglades. D) Burmese pythons carry diseases and parasites that directly impact the mammal populations of the Everglades.
Physics
1 answer:
soldier1979 [14.2K]3 years ago
8 0

Answer:

C) Burmese pythons lack natural predators and can utilize a wide variety of food sources in the Everglades.

Explanation:

Due to it being an invasive specie (naturally found in South Asia), and also one of the five largest species of snakes in the world, the Burmese pythons lack natural predators in this new territories.

The Burmese viper is also an opportunistic hunter and would eat anything it can overpower, it easily made a wide range of food varieties in these swamps.

You might be interested in
Why do we get headaches?
user100 [1]
Being hot or not drinking enough fluids.
5 0
4 years ago
Read 2 more answers
A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,00
Nutka1998 [239]

Answer:

6.99535\times 10^{-6}\ V/m

Explanation:

P = Power Output = 1000 W

r = Radius = 35000000 m

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

c = Speed of light = 3\times 10^8\ m/s

Intensity of Electric radiation is given by

I=\dfrac{P}{A}\\\Rightarrow I=\dfrac{P}{4\pi r^2}\\\Rightarrow I=\dfrac{1000}{4\pi\times 35000000^2}\ W/m^2

Intensity of Electric radiation is given by

I=\dfrac{1}{2}c\epsilon_0E_0\\\Rightarrow E_0=\sqrt{\dfrac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\dfrac{2\times \dfrac{1000}{4\pi\times 35000000^2}}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=6.99535\times 10^{-6}\ V/m

The amplitude of the electric field vector is 6.99535\times 10^{-6}\ V/m

6 0
4 years ago
Determine the magnitude as well as direction of the electric field at point A, shown in the above figure. Given the value of k =
Pavlova-9 [17]

Answer:

The magnitude of the electric field is 8.99*10^{12}N/C in the r direction.

Explanation:

The equation of the electric field is given by:

|\vec{E}|=k\frac{q}{r^{2}}

Where:

  • k is the Coulomb constant is 8.99 *10^{9}\: Nm^{2}C^{-2}
  • q is the charge
  • r is the distance from A to q

|\vec{E}|=8.99*10^{9}\frac{12.5}{0.11^{2}}    

\vec{E}=9.29*10^{12} \vac{r} \: N/C

Therefore, the magnitude of the electric field is 8.99*10^{12}N/C in the r direction.

I hope it helps you!

4 0
3 years ago
A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
4 years ago
Witch of the following is not considered to be a greenhouse gas
nevsk [136]
None of the above, nothing is there
7 0
3 years ago
Read 2 more answers
Other questions:
  • A line of dominos falling one by one is an example of energy ________ .
    12·2 answers
  • What are the reactants in the reaction? What are their properties?
    13·1 answer
  • Heat is absorbed during which of the following changes?
    6·2 answers
  • How to make a paper airplane curve down and fly upside down?
    5·2 answers
  • How do gravity assists in rock being transported to a new place
    6·1 answer
  • Two cars are sitting still. Car A has a mass of 2000 kilograms. Car B has a mass of 4000 kg. If the goal is to push both cars to
    13·1 answer
  • For a given substance, the molecules<br> move fastest when the substance is
    8·1 answer
  • What mass of lead has the same volume as 1600kg of gasoline?
    8·1 answer
  • Describe a situation in which friction changes the direction of a moving object.​
    5·2 answers
  • Water flows through a 4.50-cm inside diameter pipe with a speed of 12.5 m/s. At a later position, the pipe has a 6.25-cm inside
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!