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3 years ago

The length of a rectangular deck is 5 times its width. If the deck’s perimeter is 24 feet, what is the deck’s area?

Mathematics

1 answer:

spayn [35]3 years ago

5 0

Answer:

20ft²

Step-by-step explanation:

Let the length = L

Let the width = W

Perimeter of a rectangle = 2L + 2W

Translating the word problem into an algebraic equation, we have;

L = 5W .......equation 1

2L + 2W = 24 ........equation 2

To find the width

Substituting equation 1 into equation 2, we have;

2(5W) + 2W = 24

10W + 2W = 24

12W = 24

W = 24/12

Width, W = 2 ft

To find the length;

Substituting the value of "W" into equation 1, we have;

L = 5W

L = 5*2

L = 10 ft

To find the area of the rectangle;

Area = LW

Area = 10*2

<em>Area = 20 ft²</em>

Therefore, the deck's area is 20 feet square.

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3 years ago

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babunello [35]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given:

Diameter of given can = 3 inches

Height of given can = 5 inches

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Radius of can = 3 / 2 = 1.5 inch

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Lateral surface area of can = 2πrh

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