Answer:
20ft²
Step-by-step explanation:
Let the length = L
Let the width = W
Perimeter of a rectangle = 2L + 2W
Translating the word problem into an algebraic equation, we have;
L = 5W .......equation 1
2L + 2W = 24 ........equation 2
To find the width
Substituting equation 1 into equation 2, we have;
2(5W) + 2W = 24
10W + 2W = 24
12W = 24
W = 24/12
Width, W = 2 ft
To find the length;
Substituting the value of "W" into equation 1, we have;
L = 5W
L = 5*2
L = 10 ft
To find the area of the rectangle;
Area = LW
Area = 10*2
<em>Area = 20 ft²</em>
Therefore, the deck's area is 20 feet square.
