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2 years ago

12

What is the area of a rectangle with a length of 3 cm and width of 4.5 cm

1 answer:

____ [38]2 years ago

3 0

13.5 because 4.5 times 3 is 13.5

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10. A bin of books at a bookstore had a 60% markdown off the original price and also offered a 35% coupon to the first 200 custo

valkas [14]

Answer:

300%

Step-by-step explanation:

bc i know

6 0

3 years ago

Read 2 more answers

Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

4 0

1 year ago

Whats is the Least common multiple of 9 and 22

m_a_m_a [10]

The LCM of 9 and 22 is 1

4 0

2 years ago

Cynthia Besch wants to buy a rug for a room that is 1919 ft wide and 2727 ft long. She wants to leave a uniform strip of floor a

yulyashka [42]

Answer:

The dimension of the rug would be 17 ft × 9 ft.

Step-by-step explanation:

Given

length of the room = 27 ft.

width of the room = 19 ft.

suppose, she leaves a uniform strip of x ft. around the rug.

So,

The length of rug = (27-2x)ft.

Width of rug= (19-2x)ft.

∴ Area of the rug= length×width

$= (27-2x)(19-2x)$

$= 513-54x-38x+4x^2$

$= 513-92x+4x^2$

According to the question,

$513-92x+4x^2=153$

$513-92x+4x^2-153=0$ ( subtract 153 both sides)

$4x^2-92x+360=0$

$4(x^2-23x+90)=0$

$x^2-23x+90=0$

$x^2-(18+5)x+90=0$ ( Middle term splitting)

$x^2-18x-5x+90=0$

$x(x-18)-5(x-18)=0$

$(x-5)(x-18)=0$

$x-5=0$ or $x-18=0$ ( zero product property)

$x=5$ or $x=18$

if x=18, dimension would be negative ( Not possible)

Thus, x= 5

Hence,

length of rug= 27-10=17 ft.

width of rug= 19-10=9 ft.

8 0

3 years ago

Write an equation of a line that is parallel to 3x+2y=6 that passes through the points (4,2)

vova2212 [387]

The answer to the question

4 0

3 years ago