Remember that the formula for simple interest is:
![I=prt](https://tex.z-dn.net/?f=I%3Dprt)
Where I is the interest to paid, p is the loan, r is the interest rate (in decimal), and t is the time (in years).
A. We know that the interest rate for a loan of 9 months is 2.9%, but we need to convert that rate to decimal. To do that just divide the interest rate by 100%:
![\frac{2.9}{100} =0.029](https://tex.z-dn.net/?f=%20%5Cfrac%7B2.9%7D%7B100%7D%20%3D0.029)
Next, we are going to find the time t in years. Since the period of time is 9 months, we are going to dive by 12, the number of months in a year, to obtain the time in years:
![t= \frac{9}{12} =0.75](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7B9%7D%7B12%7D%20%3D0.75)
Now, we just need to replace the values in our formula to find the interest owned:
![I=(900)(0.029)(0.75)=19.58](https://tex.z-dn.net/?f=I%3D%28900%29%280.029%29%280.75%29%3D19.58)
We can conclude that <span>the interest owed for a home improvement loan of $900 after 9 months is $19.58.
</span>
B. Similarly:
![r= \frac{3.1}{100} =0.031](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B3.1%7D%7B100%7D%20%3D0.031)
![t= \frac{18}{12} =1.5](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7B18%7D%7B12%7D%20%3D1.5)
![I=(2500)(0.031)(1.5)=116.25](https://tex.z-dn.net/?f=I%3D%282500%29%280.031%29%281.5%29%3D116.25)
We can conclude that the interest owed for a home improvement loan of $2500 after 18 months is $116.25.
C. Similarly:
![r= \frac{2.4}{100} =0.024](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B2.4%7D%7B100%7D%20%3D0.024)
![t= \frac{6}{12} =0.5](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7B6%7D%7B12%7D%20%3D0.5)
![I=(5600)(0.024)(0.5)=67.2](https://tex.z-dn.net/?f=I%3D%285600%29%280.024%29%280.5%29%3D67.2)
We can conclude that the interest owed for a home improvement loan of $5600 after 6 months is $67.2
Each part would be 20z of Clay
This question is not correctly written.
Complete Question
Select all equations that can represent the question: "How many groups of 4/5 are in 1?" A ?⋅1=4/5? Times 1 is equal to 4 fifths B 1⋅4/5=?1 times 4 fifths is equal to ? C 4/5÷1=?4 fifths divided by 1 is equal to ? D ?⋅4/5=1? Times 4 fifths is equal to 1 E 1÷4/5=?1 divided by 4 fifths is equal to ?
Answer:
D ?⋅4/5=1 = ? Times 4 fifths is equal to
E 1÷4/5=? = 1 divided by 4 fifths is equal to
Step-by-step explanation:
How many groups of 4/5 are in 1?
The operation used to solve this is that Division operation.
Hence, we solve it by saying:
1 ÷ 4/5 = ?
= 1× 5/4 = ?
5/4 = ?
Cross Multiply
5 = 4 × ?
? = 5/4
The equations that can represent the question: is
Option D ?⋅4/5=1 = ? Times 4 fifths is equal to
Option E 1÷4/5=? = 1 divided by 4 fifths is equal to
Answer: H = 8 cm
Step-by-step explanation: Since a triangle's area is b times h/2, we know that two times 48 is 96, therefore we can opposite the equation so 12 is the base times the height (8 cm) is 96 divided by 2, there's your answer.
Answer:
The value of each share decreased by $8.
Step-by-step explanation:
Number of shares of a certain stock Linda owned = 4
Total value of shares went down by = $32
So find the change in value of each share.
Solution:
Let the total value of each share in dollars be = ![x](https://tex.z-dn.net/?f=x)
Value of 4 shares in dollars will be = ![4x](https://tex.z-dn.net/?f=4x)
The total value of shares went down by $32
So, new value of 4 shares = ![4x-32](https://tex.z-dn.net/?f=4x-32)
New value of each share = ![\frac{New\ value\ of\ total\ shares}{4}](https://tex.z-dn.net/?f=%5Cfrac%7BNew%5C%20value%5C%20of%5C%20total%5C%20shares%7D%7B4%7D)
⇒ ![\frac{4x-32}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B4x-32%7D%7B4%7D)
Splitting the denominators.
⇒ ![\frac{4x{{4}-\frac{32}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B4x%7B%7B4%7D-%5Cfrac%7B32%7D%7D%7B4%7D)
⇒ ![x-8](https://tex.z-dn.net/?f=x-8)
Original value of each share in dollars was = ![x](https://tex.z-dn.net/?f=x)
New value of each share in dollars = ![x-8](https://tex.z-dn.net/?f=x-8)
Thus, we can see that the value of each share decreased by $8.