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Andrej [43]
3 years ago
12

How do I solve these 2 problems? What’s the answer

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

1. substitution

2. transitive property

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If line uw bisects angle tuv,, m angle tue = (13x-5) and angle wuv = (7x+31) find the value of x
scZoUnD [109]

The value of x will be 6

<u><em>Explanation</em></u>

According to the below diagram, UW is the angle bisector of ∠TUV

<u>That means,</u>  \angle TUW = \angle WUV

Given that,  \angle TUW = 13x-5 and \angle WUV= 7x+31

So, the equation will be......

13x-5=7x+31\\ \\ 13x-7x=31+5\\ \\ 6x=36\\ \\ x=\frac{36}{6}=6

So, the value of x will be 6.

4 0
3 years ago
A family went to a restaurant for dinner. The bill before tax and tip was $52.78. The sales tax is
Sergeeva-Olga [200]

Answer:

B

Step-by-step explanation:

52.78×6.5%=3.43

52.78×18%=9.50

52.78+3.43+9.50=65.71

4 0
2 years ago
Below are 36 sorted ages of an acting award winner. find the percentile corresponding to age 3838 using the method presented in
horrorfan [7]

Question:

Below are 36 sorted ages of an acting award winner. find the percentile corresponding to age 38 using the method presented in the textbook. 18 19 20 20 21 23 25 31 33 34 35 37 38 47 50 51 55 55 58 59 62 62 64 66 69 70 70 70 71 71 72 74 74 75 77 80 percentile of value 38 = ______ ​(round to the nearest integer as​ needed.)

Answer:

33 percentile

Step-by-step explanation:

Given the ages:

18, 19, 20, 20, 21, 23, 25, 31, 33, 34, 35, 37, 38, 47, 50, 51, 55, 55, 58, 59, 62, 62, 64, 66, 69, 70, 70, 70, 71, 71, 72, 74, 74, 75, 77, 80.

We are told to find the percentile corresponding to age 38.

To find the percentile corresponding to age 38 simply means to find the percentage of ages that are less than 38.

From the given values, the number of ages less than 38 are 12. Therefore, the percentile corresponding to age 38 would be:

(Ages less than 38/ total number of ages) * 100

= \frac{12}{36} * 100 = 33.333

33.333 ≈ 33

The percentile corresponding to age 38 = 33 percentile

5 0
3 years ago
SAT Help
posledela
Well, their speeds are (V_1 is Jack's speed, and V_2 is Richard's.
V_1 = \frac{1}{5} houses/day \\ V_2 = \frac{1}{7} houses/day \\ V = V_1 + V_2 = \frac{1}{5}+\frac{1}{7} = \frac{7+5}{35} = \frac{12}{35}
They, together, can paint 12 houses in 35 days. To get a single house, we only have to calculate \frac{35}{12} which is very close to 3 (a bit below)
5 0
3 years ago
Read 2 more answers
I’m sorry I keep asking for help I’m not at my best self right now. Can you guys please help me again?
Semenov [28]

Answer:

which ones you want solved? all?

Step-by-step explanation:

7 0
2 years ago
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