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nata0808 [166]
3 years ago
6

A child with cystic fibrosis has a mutated protein in his cells which does not behave normally. The mutated protein stops chlori

de ions from leaving the cells. This causes water to be retained in the cell creating thicker fluids. These fluids cause a buildup of mucus which leads to breathing problems. Which cell structure is most likely being negatively affected by the mutated protein?
Chemistry
1 answer:
Helen [10]3 years ago
6 0

Answer:

Explanation:

lung air ways the mucus will clog it up causing asthma hope this helped :P

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I really need help, I don’t know what to do on this
Shtirlitz [24]

Answer:

A: dependent variable

B: experimental group

C: independent variable

D: control variables

E: control group

Explanation:

7 0
3 years ago
Which of the following compounds are soluble in aqueous solutions? Select ALL that are soluble.
sattari [20]
<h3>Answer:</h3>
  • K₂S
  • CaSO₄ (slightly soluble in water)
  • Pb(ClO₄)₂
<h3>Explanation:</h3>
  • Mg(OH)₂  and CoCO₃ are insoluble in water.
  • Solubility rules are used to determine whether a compound will be soluble or not soluble in aqueous form.
  • K₂S is soluble in aqueous solutions as all salts of Potassium are soluble in water.
  • Calcium (ii) sulfate is slightly soluble in water.
  • Hydroxides are insoluble in water except, KOH, NaOH and NH₄OH.and Barium hydroxide. Therefore, Mg(OH)₂ is an insoluble hydroxide.
  • CoCO₃ is insoluble since carbonates are insoluble except K₂CO₃, Na₂CO₃ and (NH₄)₂CO₃. .
  • Pb(ClO₄)₂ is soluble because all perchlorates are soluble.
7 0
3 years ago
Question 1
mel-nik [20]
One is ocean
Two is green house effect is the trapping of gas in the atmosphere and global warming is the heating of the earth
Three is option one
3 0
3 years ago
The volume of a gas is 5.0 L at 278 K. If the temperature of the gas
goldfiish [28.3K]

Answer: O 10.1 is your answer! Please mark me as brainlyest!?

6 0
3 years ago
Jacob carelessly added only 40.0 mL (instead of the recommended 50.0 mL) of 1.1 M HCl to the 50.0 mL of 1.0 M NaOH. Explain the
Sati [7]

Answer:

Explanation:

mole of NaOH present = molarity x volume

                                     = 1.0 X 0.05 = 0.05 mole

<em>Recommended mole of HCl </em>= 1.1 x 0.05 = 0.055

<em>Mole of HCl carelessly added by Jacob </em>= 1.1 x 0.04 = 0.044

From the equation of reaction:

HCl + NaOH ----> NaCl + H2O

The ratio of mole of HCl to that of NaOH for a complete neutralization reaction is 1:1. However, the recommended mole of HCl (0.055 mole) is more than the mole of NaOH (0.05 mole). <u>Hence, the recommended endpoint of the reaction is supposed to be acidic.</u>

The mole of HCl added by Jacob (0.044) is short of the recommended amount (0.055) and also short of the amount required for a neutral endpoint (0.05). <u>This means that the endpoint will have an excess amount of NaOH and as such, basic instead of the desired acidic endpoint.</u>

8 0
3 years ago
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