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nata0808 [166]
4 years ago
6

A child with cystic fibrosis has a mutated protein in his cells which does not behave normally. The mutated protein stops chlori

de ions from leaving the cells. This causes water to be retained in the cell creating thicker fluids. These fluids cause a buildup of mucus which leads to breathing problems. Which cell structure is most likely being negatively affected by the mutated protein?
Chemistry
1 answer:
Helen [10]4 years ago
6 0

Answer:

Explanation:

lung air ways the mucus will clog it up causing asthma hope this helped :P

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Need help ASAP DUE IN LIKE 2 minutes!!!!!!! Points are added
I am Lyosha [343]

Proton:

Positive

Found in Nucleus

Mass of 1 AMU

Neutron:

Neutral

Found in Nucleus

Mass of 1 AMU

Electron:

Negative

Found in orbitals

Mass of 0 AMU

Please mark Brainliest if this helped you! :)

7 0
3 years ago
How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?
Kipish [7]

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ <em>C</em> KOH = 0.0050 N = 0.0050  eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

4 0
3 years ago
3. Classify the following plants along with two main characteristics: al Cycus b) Bamboo c) Lemna d) Paddy a) Sugarcane f) Pinus
madreJ [45]

Answer:

A. cycas

1. it is thick and scaly

2. it grow relatively slowly and have a large, terminal rosette of leaves.

B. bamboo

1. it is very durable

2. it is both flexible and elastic

C. lemna

1. it grows as simple free-floating thalli on or just beneath the water surface

2. it are small, not exceeding 5 mm in length

D. paddy

1. it is variety purity

2. it degree of purity

E. sugarcane

1. it is bear long sword-shaped leaves

2. it's stalks are composed of many segments, and in each joint there is a bud

4 0
2 years ago
The Bay of Fundy in Nova Scotia, Canada is reported to have the largest tides in the world with high tide and low tide occurring
topjm [15]

The rate in m/s is 5.2 * 10^-4 m/s.

<h3>What is the rate in m/s?</h3>

We know that the speed is given as the ratio of the distance covered to the time taken. In this case, we have been told that the rate at which the tide rises is 6.08 ft per hour. We would now need to convert the rate from  6.08 ft per hour to m/s.

Now;

We know that;

1 foot/hour = 8.5 * 10^-5 m/s

6.08 ft per hour = 6.08 ft per hour * 8.5 * 10^-5 m/s/1 foot/hour

= 5.2 * 10^-4 m/s

Learn more about speed:brainly.com/question/28224010

#SPJ1

3 0
2 years ago
Help me please omg
Sever21 [200]

Answer:

NH₃

M = n/V(L)

0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Explanation:

Step 1: Given and required data

  • Volume of solution (V): 375. mL
  • Molar concentration of the solution (M): 2.25 M
  • Chemical formula for ammonia: NH₃

Step 2: Calculate the moles (n) of ammonia (solute)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V(L)

n = M × V(L)

n = 2.25 mol/L × 0.375 L = 0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

4 0
3 years ago
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