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Scorpion4ik [409]
3 years ago
14

. Using the following equation: F = ma Solve for m (1 point)

Chemistry
1 answer:
Oksanka [162]3 years ago
6 0
<span>To solve for m in the equation F = ma, you must divide both side of the equation by a. This will make the equation look like F/a = ma/a. Since m is being multiplied by a, dividing it will cancel out. Now making the final equation look like F/a=m and/or m=F/a.</span>
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The speed of light is 3.0 x 10^8 m.s^-1. what is the speed in nm.ms^-1 ?
snow_lady [41]

Answer:

c=3\times 10^{17}\ nm/s

Explanation:

The speed of light is 3\times 10^8\ m/s. It is required to convert it into nm/s.

The relation between nm and m is as follows :

1\ nm=10^{-9}\ m\\\\1\ m=10^9\ nm

So,

c=3\times 10^8\ m/s \\\\c=3\times 10^8\times 10^9\ nm/s\\\\c=3\times 10^{17}\ nm/s

So, the speed of light is 3\times 10^{17}\ nm/s.

8 0
3 years ago
Calculate the Molarity of 89.94 g NaCl is dissolved in 1249 mL of solution.
tino4ka555 [31]

Answer:

The molarity of the solution is 1, 23 M.

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

89,94 g ---------x= (89,94 g x 1 mol NaCl)/58, 5 g= 1,54 mol NaCl

1249 ml solution------ 1,54 mol NaCl

1000ml solution------x= (1000ml solutionx 1,54 mol NaCl)/1249 ml solution

x=1,23 mol NaCl---> The solution is 1, 23 molar (1,23 M)

7 0
3 years ago
At what temp does h2o melt
s344n2d4d5 [400]

Answer:

32 degrees fahrenheit

Explanation:

6 0
3 years ago
Read 2 more answers
What are the characteristics shapes of s p and d orbitals
german

Answer:

Explanation:

S orbital has a spherical shape

P orbital has a dumb-bell shape

d orbital has a double dumb-bell shape

3 0
3 years ago
The combustion of propane may be described by the chemical equation, 
olasank [31]
\nu_{C_3H_8}=\frac{40.4}{\mu_{C_3H_8}}=
=\frac{40.4}{3A_C+8A_H}=\frac{40.4}{44}=
=\frac{9}{10}=0.9mol
1mol\ C_3H_8...5\ mol\ O_2 \\ 0.9mol\ C_3H_8...x\ mol\ O_2
x=\frac{0.9*5}{1}=4.5mol\ O_2
m=\mu_{O_2}*x=2*A_O*4.5=9*8=72g\ O_2
6 0
4 years ago
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