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3 years ago

. Using the following equation: F = ma Solve for m (1 point)

1 answer:

6 0

<span>To solve for m in the equation F = ma, you must divide both side of the equation by a. This will make the equation look like F/a = ma/a. Since m is being multiplied by a, dividing it will cancel out. Now making the final equation look like F/a=m and/or m=F/a.</span>

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Help meeee!<br> 3874 dkg = _____ dg

musickatia [10]

Answer:

the answer is 387400 but I might be wrong

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3 years ago

(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction

ale4655 [162]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

$Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2$

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

$m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2$

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

$m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu} \\\\m_{Cu}=0.380gCu$

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

$m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3} \\\\m_{AgNO_3}=2.03gAgNO_3$

Best regards!

5 0

3 years ago

Write the formulas of the compounds formed by NH4+ with the following anions: NO3−, HCO3−, SO32−, PO43−. Use the given order of

tekilochka [14]

NH₄NO₃
NH₄HCO₃
(NH₄)₂SO₃
(NH₄)₃PO₄

5 0

3 years ago

C6H12O6 + 6O2 → 6CO2 + 6H2O is the chemical equation for cellular respiration. What are the products in this reaction?

maks197457 [2]

Answer:

The products are: A) CO2, H2O

Explanation:

Those products that are seen on the right side of the reaction (that is, those substances that are generated from the reagents). In this case they are carbon dioxide and water.

The general equation of cellular respiration is:

C6H1206 + 602 -> 36 ATP + 6CO2 + 6H20

4 0

3 years ago

Matter in the ____state completely fills the volume of its container

balu736 [363]

Answer:

Gas state

Explanation:

Gas particles spread out to fill a container evenly, unlike solids and liquids.

5 0

3 years ago

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