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3 years ago

What is the solution set?

Mathematics

2 answers:

Ludmilka [50]3 years ago

8 0

Answer:

- 1.45

Step-by-step explanation:

Novay_Z [31]3 years ago

3 0

Answer: x = 1 so 1/2 - 4/1 + 8 = 0n

Step-by-step explanation:

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Tell whether the angles are adjacent or vertical. Then find the value of x.

Artist 52 [7]

Answer:

These are Vertical angles, adjacent angles are next to each other and make up a whole angle, while vertical angles are across and equal the same thing.

X = 81 because 84 and (x + 3) are the same so 84 minus 3 is 81

Hope that helps

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2 years ago

Shirley wants to buy a skateboard for $64. She has $98 in her account. She spent $10.85 to buy stationary. She also wants to buy

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3 years ago

Gabriel bought a purse that was on sale at 10% off. If she paid $59.95, including tax, and the sales tax rate was 6%, how much d

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3 years ago

Solving a right triangle (round to the nearest tenth)

Inga [223]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for A

A = 180° - (90 + 46)° = 180° - 136° = 44°

----------------------------------------------------------------

tan46° = $\frac{opposite}{adjacent}$ = $\frac{b}{23}$

Multiply both sides by 23

23 × tan46° = b, thus

b ≈ 23.8 ( to the nearest tenth )

-----------------------------------------------------------------

cos46° = $\frac{adjacent}{hypotenuse}$ = $\frac{23}{c}$

Multiply both sides by c

c × cos46° = 23 ( divide both sides by cos46° )

c = $\frac{23}{cos46}$ ≈ 33.1 ( to the nearest tenth )

5 0

3 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago