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Verizon [17]
3 years ago
14

Find two consecutive whole numbers that square root of 31 lies between. answer this please.

Mathematics
1 answer:
Sidana [21]3 years ago
7 0

Given :

An irrational number , x=\sqrt{31} .

To Find :

Two consecutive whole numbers that square root of 31 lies between.

Solution :

We know , square root of 36 is 6.

Also, square root of 25 is 5.

Now, we can see that \sqrt{31} lies between 5 and 6. Also, both 5 and 6 are consecutive.

Therefore, between 5 and 6 is the solution.

Hence, this is the required solution.

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Can somebody help me on 23 and 24, it’s geometry
alexdok [17]

Answer:

  23.  x = 4; DE = 44

  24.  x = 25; DS = 28

Step-by-step explanation:

23. Point S is the midpoint of DE, so ...

  DS = SE

  3x +10 = 6x -2

  12 = 3x . . . . . . . . . add 2-3x

  4 = x . . . . . . . . . . . divide by 3

Then DS has length ...

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and DE is twice that length, so ...

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__

24. DS is half the length of DE, so is ...

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  DS = 28

Then x can be found from ...

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_____

<em>Comment on problem 24</em>

Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.

8 0
3 years ago
Read 2 more answers
How do you simplify -2x(x+3)-(x+1)(x-2)
Elena L [17]
1. Distribute the -2x with the (x+3)
2.Multiply (x+1) and (x-2) which is (x2- x -2)
So far it should look like (-2x^2 -6x) - (x^2-x-2)
3. Distribute out the negative
Should look like this -2x^2 -6x - x^2+x+2
4. Lastly combine like terms

Your result should be:
-3x^2 - 5x + 2

Hope this helps!
8 0
2 years ago
Read 2 more answers
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