Convert 22.625 into a fraction

The triangles shown are similar. Which similarity statement expresses the relationship between the two triangles?

Pani-rosa [81]

Answer:

The similarity statement that expresses the relationship with the two triangles is that "Triangle P Q R is similar to Triangle W X Y"

Step-by-step explanation:

In drawing and labeling triangles, the three angles are labeled with letters that follow alphabetically. Thus, a triangle A B C should be in similarity with triangle x y z. Like wise from the above statements, triangle P R Q can only be similar in labeling in the range of W X Y even if the figures are not shown.

5 0

3 years ago

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You invest $1,300 in an account that has an annual interest rate of 5%, compounded annually. How much money will be in the accou

KIM [24]

Answer:

A=Pe^rt

P= princible (1300)

e= (2.71828)- function on a graphing calculator

r = interest rate (.05 or 5%)

t = time (10 years)

A = 1300e^.05(10)

A = 1300e^.5

A = 2143.337652

A = 2143

7 0

3 years ago

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What does X equal in 4x+1=5x-4

weeeeeb [17]

Answer:

x = 5

Step-by-step explanation:

4x - 5x + 1 = -4

4x - 5x = -4-1

-x = -5

x = 5

Hope this helped

Brainliest is Appreciated.

5 0

3 years ago

Find the sample size necessary in order to be 95% confident when determining the true mean weight within 2 units (EC2). Assume t

bogdanovich [222]

Answer:

(c) 43.

Step-by-step explanation:

Given:

Margin of error (E) = 2

Sample variance $(s^{2})$ = 44

Confidence level = 95%

The z- value at 95% confidence level is 1.96.

The sample using the provided information can be calculated as:

$n=(\frac{z(s)}{E})^{2} \\n=\frac{z^{2} s^{2} }{E^{2} } \\n=\frac{1.96^{2} (44) }{2^{2} }\\n= 42.52\\n=43$

Hence, the correct option is (c) 43.

8 0

3 years ago

"is it appropriate to use the normal approximation for the sampling distribution of"

Katyanochek1 [597]

Answer: Normal approximation can be used for discrete sampling distributions, such as Binomial distribution and Poisson distribution if certain conditions are met.

Step-by-step explanation: We will give conditions under which the Binomial and Poisson distribitions, which are discrete, can be approximated by the Normal distribution. This procedure is called normal approximation.

1. Binomial distribution: Let the sampling distribution be the binomial distribution $B(n,p)$ , where $n$ is the number of trials and $p$ is the probability of success. It can be approximated by the Normal distribution with the mean of $np$ and the variance of $np(1-p)$ , denoted by $N(np,np(1-p))$ if the following condition is met:

$n>9\left(\frac{1-p}{p}\right)\text{ and } n>9\left(\frac{p}{1-p}\right)$

2. Poisson distribution: Let the sampling distribution be the Poisson distribution $P(\lambda)$ where $\lambda$ is its mean. It can be approximated by the Normal distribution with the mean $\lambda$ and the variance $\lambda$ , denoted by $N(\lambda,\lambda)$ when $\lambda$ is large enough, say $\lambda>1000$ (however, different sources may give different lower value for $\lambda$ but the greater it is, the better the approximation).

5 0

3 years ago