All categories

2 years ago

Please help me, this is due in 2 hours and I need this done plz.

Mathematics

1 answer:

bija089 [108]2 years ago

5 0

Answer:

It's probably it

Step-by-step explanation:

A = (-4, -2)

B = (1, 6)

Imagine a new point (C) where they intersect (1, -2)

Now we can form a triangle, the distance between A and B will be the hypotenuse.

h² = 5² + 8²

h² = 25 + 64

h² = 89

h = $\sqrt{89}$

h = ~9.43...

h = 9

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(½) (6x + 3) = 7 – (3x + 1)

erastovalidia [21]

$\tt Step-by-step~explanation:$

To solve for x, we have to remember to isolate the variable.

$\tt Step~1:$

For 1/2, we can make that 0.5, since their values are equivalent. Our equation:

$\tt (0.5)(6x+3)=7-(3x+1)$

Let's distribute the 0.5 first.

$\tt 0.5*6x=3x\\0.5*3=1.5$

$\tt Step~2:$

Now, let's simplify the right side of the equation. We have to distribute the negative to 3x and 1.

$\tt -1*3x=-3x\\-1*1=-1$

Then, we simplify the entire expression.

$\tt 7-3x-1=-3x+6$

$\tt Step~3:$

Our equation now:

$\tt 3x+1.5=-3x+6$

Let's add 3x to the right and 3x to the left to simplify the -3x on the right side of the equation.

$\tt 3x(+3x)+1.5=-3x (3x)+6\\6x+1.5=6$

$\tt Step~4:$

Let's do the same thing we did in Step 3 to 1.5. Subtract 1.5 on both sides of the equation.

$\tt 6x+1.5(-1.5)=6(-1.5)\\6x=4.5$

$\tt Step~5:$

Finally, we divide both sides by 6 to isolate x.

$\tt \frac{6x}{6} =x\\\frac{4.5}{6}= 0.75~or~\frac{3}{4}$

$\large\boxed{\tt Our~final~answer:~x=0.75~(or~\frac{3}{4})}$

8 0

3 years ago

How many 5 letter combinations can be created from the letters in the word friendly?

WARRIOR [948]

56 is the answer 56 5 letter combinations

8 0

3 years ago

In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (

DENIUS [597]

Answer:

a) T is not homogeneous
b) T is not additive
c) T is not homogeneous
d) T is not additive
e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

a) $T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0)$ . These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).

b) $T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5)$ . Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).