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4 years ago

Why isn't Coulomb's law valid for large conducting objects, even if they are spherically symmetrical?

Physics

1 answer:

VikaD [51]4 years ago

6 0

Answer:

The Coulomb’s Law is as follows

$\vec{F} = \frac{1}{4\pi \epsilon_0}\frac{q_1q_2}{r^2}\^r$

According to this law, the force between two charged objects can be calculated using the distance between the objects. If the objects are large, then it is not possible to determine the distance, r, between that object and the other object. Because, the edge of the object contain charges as well as the center of the object.

In that case, you need to separate the object into infinitesimal points, apply the formula to those points, then integrate over the large object to find the force between objects.

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Jim travelled the first 3 hours of his journey at speed of 60 mph and the remaining 5 hours at 24 mph how long is the whole jour

frosja888 [35]

Distance of first instance = speed * Time
= 60 * 3 = 180 miles

Distance of second instance = speed * Time
= 24 * 5 = 120 miles

So, Total Distance = 180 + 120 = 300 miles

In short, Your Answer would be 300 miles

Hope this helps!

4 0

3 years ago

What is a hypothesis?

Likurg_2 [28]

Answer:

Explanation:

a statement that can be tested through the scientific method

4 0

3 years ago

A bike race against the clock takes place on a straight road. Yan drives at 37 km / h and he starts the course 30s before Christ

joja [24]

Given data:

Yan speed;

$u_1=37\text{ km/h}$

Christopher speed;

$u_2=38.9\text{ km/h}$

Christophe starts 30 s later than Yan. Therefore, Christophe takes 30 s less than Yan to reach the same distance.

Part (A)

The distance is given as,

$d=ut$

Let both Yan and Christophe meet at d distance from the start position. Therefore,

$u_1t=u_2(t-30)$

Substituting all known values,

$\begin{gathered} (37\text{ km/h})t=(38.9\text{ km/h})\times(t-30) \\ \frac{(37\text{ km/h})}{(38.9\text{ km/h})}=\frac{(t-30)}{t} \\ 0.95=1-\frac{30}{t} \\ \frac{30}{t}=1-0.95 \\ \frac{30}{t}=0.05 \\ t=\frac{30}{0.05} \\ t=600\text{ s} \end{gathered}$

Therefore, 600 s after Yan's departure Christophe will join him.

Part (B)

The distance is given as,

$d=u_1t$

Substituting all known values,

$\begin{gathered} d=(37\text{ km/h})\times(600\text{ s}) \\ =(37\text{ km/h})\times(600\text{ s})\times(\frac{1\text{ hr}}{3600\text{ s}}) \\ \approx6.17\text{ km} \end{gathered}$

Therefore, Christophe joins Yan after 6.17 km from the start.

3 0

1 year ago

Do political maps change

lesantik [10]

I think the answer is yes because earth changes overtime.

7 0

3 years ago

The trachea splits into two branches called larynx true or false<br> pls answer somebodyyyyyyy

kirill115 [55]

Answer:

False

Explanation:

The trachea divides into left and right air tubes called bronchi, which connect to the lungs. Within the lungs, the bronchi branch into smaller bronchi and even smaller tubes called bronchioles.

Hope this helps :)

7 0

3 years ago