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Ray Of Light [21]
2 years ago
12

Where does gasoline come from?

Physics
2 answers:
ss7ja [257]2 years ago
8 0

Answer:

the ground..

Explanation:

quester [9]2 years ago
7 0

Answer: Gasoline comes from the ground.

Explanation:

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Much of the bedrock in Virginia’s Piedmont region, originally formed by cooled magma, has re-crystallized under a great deal of
3241004551 [841]

A) gneiss

Explanation:

The likely rock that would be found here is gneiss.

A rock type that forms under a great deal of temperature and pressure is a metamorphic rock.

Such rocks would have their minerals crystallized when subjected to these extreme conditions.

  • Metamorphic rocks are changed rocks that are formed when minerals in rocks are subjected to extreme pressure and temperature before they start melting.
  • These rock type can form from either sedimentary or igneous rocks. In fact a metamorphic rock can also change into another one.
  • Examples of metamorphic rocks are gneiss, schist, hornfels, marble etc.

Halite, limestone and sandstone are examples of sedimentary rocks that forms by the accumulation of sediments or precipitation of ions form solutions.

learn more:

Metamorphic change brainly.com/question/869769

#learnwithBrainly

6 0
4 years ago
A cubical box measuring 1.29 m on each side contains a monatomic ideal gas at a pressure of 2.0 atm How much thermal energy do t
Marrrta [24]

Answer:

a) U = 652.545\,kJ, b) v \approx 659.568\,\frac{m}{s}

Explanation:

a) According to the First Law of Thermodinamics, the system is not reporting any work, mass or heat interactions. Besides, let consider that such box is rigid and, therefore, heat contained inside is the consequence of internal energy.

Q = U

The internal energy for a monoatomic ideal gas is:

U = \frac{3}{2} \cdot n \cdot R_{u} \cdot T

Let assume that cubical box contains just one kilomole of monoatomic gas. Then, the temperature is determined from the Equation of State for Ideal Gases:

T = \frac{P\cdot V}{n\cdot R_{u}}

T = \frac{(202.65\,kPa)\cdot(1.29\,m)^{3}}{(1\,kmole)\cdot(8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K} )}

T = 52.325\,K

The thermal energy contained by the gas is:

U = \frac{3}{2}\cdot (1\,kmole)\cdot (8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K})\cdot (52.325\,K)

U = 652.545\,kJ

b) The physical model for the cat is constructed from Work-Energy Theorem:

U = \frac{1}{2}\cdot m_{cat} \cdot v^{2}

The speed of the cat is obtained by isolating the respective variable and the replacement of every known variable by numerical values:

v = \sqrt{\frac{2 \cdot U}{m_{cat}}}

v = \sqrt{\frac{2\cdot (652.545 \times 10^{3}\,J)}{3\,kg} }

v \approx 659.568\,\frac{m}{s}

3 0
3 years ago
HELP what is the answer to this question?
Dennis_Churaev [7]
I think it’s c sorry if wrong
7 0
3 years ago
A fireman standing on a 15 m high ladder
ludmilkaskok [199]

Answer:

31.6 m/s

Explanation:

Mass is conserved, so the mass flow at the outlet of the pump equals the mass flow at the nozzle.

m₁ = m₂

ρQ₁ = ρQ₂

Q₁ = Q₂

v₁A₁ = v₂A₂

v₁ πd₁²/4 = v₂ πd₂²/4

v₁ d₁² = v₂ d₂²

Now use Bernoulli equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

Since h₁ = 0 and P₂ = 0:

P₁ + ½ ρ v₁² = ½ ρ v₂² + ρgh₂

Writing v₁ in terms of v₂:

P₁ + ½ ρ (v₂ d₂²/d₁²)² = ½ ρ v₂² + ρgh₂

P₁ + ½ ρ (d₂/d₁)⁴ v₂² = ½ ρ v₂² + ρgh₂

P₁ − ρgh₂ = ½ ρ (1 − (d₂/d₁)⁴) v₂²

Plugging in values:

579,160 Pa − (1000 kg/m³)(9.8 m/s²)(15 m) = ½ (1000 kg/m³) (1 − (1.99 in / 3.28 in)⁴) v₂²

v₂ = 31.6 m/s

8 0
3 years ago
When charges build up on a surface they:
NeTakaya
The awnser is A and B
6 0
4 years ago
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