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Sav [38]
3 years ago
13

The particle in the atom with a negative charge is the ______ Answer here

Physics
2 answers:
NISA [10]3 years ago
4 0

Answer:

Explanation:

The electron has a negative charge. Proton is positive and neutron is neutral.

Andrej [43]3 years ago
3 0
Electronnnnnnnnnnnnnn
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Uncle Harry weighs 750 N. What is his mass in kg?
Elenna [48]

Answer:

W = MG

750 = M * 10

M = 750/10

M = 75 kg

8 0
2 years ago
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The position of a particle is given by ~r(t) = (3.0 t2 ˆi + 5.0 ˆj j 6.0 t kˆ) m
Julli [10]

Answer:

v=(6ti+6k)\ m/s

Explanation:

Given that,

The position of a particle is given by :

r(t) = (3.0 t^2 i + 5.0j+ 6.0 tk) m

Let us assume we need to find its velocity.

We know that,

v=\dfrac{dr}{dt}\\\\=\dfrac{d}{dt}(3.0 t^2 i + 5.0j+ 6.0 tk) \\\\=(6ti+6k)\ m/s

So, the velocity of the particle is (6ti+6k)\ m/s.

5 0
3 years ago
You wish to produce an emf of 41.0 mV using an inductor whose inductance is 13.0 H. You start with a current of 1.50 mA through
Molodets [167]

Answer:

The current through the inductor at the end of 2.60s is 9.7 mA.

Explanation:

Given;

emf of the inductor, V = 41.0 mV

inductance of the inductor, L = 13 H

initial current in the inductor, I₀ = 1.5 mA

change in time, Δt = 2.6 s

The emf of the inductor is given by;

V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 =  \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.

6 0
3 years ago
A 50 kg student climbs 3m to the top of a set of stairs. Calculate the change in the student’s gravitational potential energy fr
erastova [34]
Gpe = mgh
gpe = 50*10*3
gpe = 1500 J
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2 years ago
Sodium = Na
ad-work [718]
Boron - B
Explanation
6 0
3 years ago
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