When the substance are moved close together and they move more quickly they get compressed.
The loudness was increased by the amplifier which converted electrical energy into sound energy.
Answer:
For cast iron we have
![h = 0.92 m](https://tex.z-dn.net/?f=h%20%3D%200.92%20m)
For copper
![h = 1.05 m](https://tex.z-dn.net/?f=h%20%3D%201.05%20m)
For Lead
![h = 1.23 m](https://tex.z-dn.net/?f=h%20%3D%201.23%20m)
For Zinc
![h = 2.43 m](https://tex.z-dn.net/?f=h%20%3D%202.43%20m)
Explanation:
As we know that final speed of the block is calculated by work energy theorem
![W_f + W_g = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=W_f%20%2B%20W_g%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
now we have
![-\mu_k mg cos\theta(\frac{h}{sin\theta}) + mgh = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=-%5Cmu_k%20mg%20cos%5Ctheta%28%5Cfrac%7Bh%7D%7Bsin%5Ctheta%7D%29%20%2B%20mgh%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
now we have
![v^2 = 2gh - 2\mu_k g h cot\theta](https://tex.z-dn.net/?f=v%5E2%20%3D%202gh%20-%202%5Cmu_k%20g%20h%20cot%5Ctheta)
![v = \sqrt{2gh(1 - \mu_k cot\theta)}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2gh%281%20-%20%5Cmu_k%20cot%5Ctheta%29%7D)
For cast iron we have
![4 = \sqrt{2(9.81)(h)(1 - 0.15cot52)}](https://tex.z-dn.net/?f=4%20%3D%20%5Csqrt%7B2%289.81%29%28h%29%281%20-%200.15cot52%29%7D)
![h = 0.92 m](https://tex.z-dn.net/?f=h%20%3D%200.92%20m)
For copper
![4 = \sqrt{2(9.81)(h)(1 - 0.29cot52)}](https://tex.z-dn.net/?f=4%20%3D%20%5Csqrt%7B2%289.81%29%28h%29%281%20-%200.29cot52%29%7D)
![h = 1.05 m](https://tex.z-dn.net/?f=h%20%3D%201.05%20m)
For Lead
![4 = \sqrt{2(9.81)(h)(1 - 0.43cot52)}](https://tex.z-dn.net/?f=4%20%3D%20%5Csqrt%7B2%289.81%29%28h%29%281%20-%200.43cot52%29%7D)
![h = 1.23 m](https://tex.z-dn.net/?f=h%20%3D%201.23%20m)
For Zinc
![4 = \sqrt{2(9.81)(h)(1 - 0.85cot52)}](https://tex.z-dn.net/?f=4%20%3D%20%5Csqrt%7B2%289.81%29%28h%29%281%20-%200.85cot52%29%7D)
![h = 2.43 m](https://tex.z-dn.net/?f=h%20%3D%202.43%20m)
The resistance expected of the heater is 50.1 ohms.
<h3>What is resistance?</h3>
Resistance can be defined as the opposition to the flow of electric current in an electric circuit. The S.I unit of resistance is Ohms (Ω).
To calculate the resistance of the heater, we use the formula below.
<h3>Formula:</h3>
- R = V²/P............. Equation 1
Where:
- R = Resistance of the heater
- P = Power of the heater
- V = Voltage supplied to the heater
From the question,
Given:
- V = 480 V
- P = 4.6 kW = 4600 W
Substitute these values into equation 1
- R = (480²)/4600
- R = 50.1 ohms.
Hence, the resistance expected of the heater is 50.1 ohms.
Learn more about resistance here: brainly.com/question/17563681
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