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Natalka [10]
3 years ago
7

I WILL MAKE YOU BRAINLIEST! PLEASE PROVIDE PROOF FROM K12. ASAPHURRY IS ALWAYS WELCOME TO ANSWER MY QUESTIONS SHE IS THE BEST. t

HANK YOU
What best describes the same pattern of tides on Earth throughout the day?

spring tides


neap tides


nocturnal tides


semidiurnal tides

Physics
1 answer:
ser-zykov [4K]3 years ago
3 0

Hello again! Thanks for acknowledging me in your question^^ I’m a he though^^ Okay, so moving onto my answer, it is D) semidiurnal tides. The proof that I’m going to provide to you isn’t exactly the answer but is says everyday so it should be correct. Please trust me and tell me if the answer is correct or not. I would choose that answer though. Here is proof:

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A car with a mass of 710 kg is traveling at 37 km/hr. It accelerates to a speed of 120 km/hr in 12.6 seconds. What is the net fo
guajiro [1.7K]

Answer: The net force acting on the car 1,299.3 N.

Explanation:

Mass of the car = 710 kg

Initial velocity of the car of the ,u= 37 km/h= 10.27 m/s (1km\h=\frac{5}{18} m/s)

Final velocity of the car,v = 120 km/h = 33.33 m/s

time taken b y car = 12.6 sec

v-u=at

33.33m/s-10.27m/s=23.06 m/s=a(12.6 sec)

a = 1.83 m/s^2

Force=mass\times acceleration

Force=710 kg\times 1.83 m/s^2

Force=1,299.3 N

The net force acting on the car 1,299.3 N.

8 0
3 years ago
Tara is an electrician. Which field of science does Tara need to know the most about in order to do her job?
katovenus [111]
Chemistry and physics
3 0
3 years ago
A baseball is hit into the air with a velocity of 27 m/s. How high does it go?
Marizza181 [45]

Answer:

Explanation:

If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;

Max height H = u²/2g

u is the initial velocity of the body = 27m/s

g is the acceleration due to gravity = 9.81m/s²

H = 27²/2(9.81)

H = 729/19.62

H = 37.16m

Hence the ball went 37.16m high

8 0
3 years ago
!!HELP HELP!!
borishaifa [10]

Answer:

7.5s

Explanation:

Given parameters:

Velocity  = 30m/s

Deceleration  = 4m/s²

Unknown:

Time it takes for the car to come to complete rest  = ?

Solution:

 To solve this problem, we use the kinematics expression below:

        v  = u + at

 Since this is a deceleration

         v  = u - at

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

         v - u  = -at

         0  - 30  = -4 x t

              -30  = -4t

               t  = 7.5s

6 0
3 years ago
A 700 kg racecar slowed from 30 m/s to 15 m/s. What is the change in momentum
Lerok [7]

Momentum = (mass) x (speed)

Original momentum  =  (700 kg) x (30 m/s)  =  21,000 kg-m/s

Final momentum = (700 kg) x (15 m/s)  =  10,500 kg-m/s

Change in momentum  =  - 10,500 kg-m/s .
8 0
3 years ago
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