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What best describes the same pattern of tides on Earth throughout the day?
spring tides
neap tides
nocturnal tides
semidiurnal tides
What best describes the same pattern of tides on Earth throughout the day?
spring tides
neap tides
nocturnal tides
semidiurnal tides
1 answer:
Hello again! Thanks for acknowledging me in your question^^ I’m a he though^^ Okay, so moving onto my answer, it is D) semidiurnal tides. The proof that I’m going to provide to you isn’t exactly the answer but is says everyday so it should be correct. Please trust me and tell me if the answer is correct or not. I would choose that answer though. Here is proof:
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Answer:
L=0.654 m
Explanation:
<u>Concepts and Principles </u>
1- The speed of sound in air is expressed as a function of the temperature of air as follows:
v=(331 m/s)√(1+T_C/273°C) (1)
where 331 m/s is the speed of sound in air at temperature 0°C and Tc is the temperature of air in Celsius.
<u>Standing Wave Patterns in Pipes: </u>
A pipe open at both ends can have standing wave patterns with resonant frequencies:
f=v/λ=nv/2L n=1,2,3.........
where v is the speed of sound in air.
<u>Given Data </u>
f_1 (fundamental frequency of the flute) = 262 Hz
T (temperature of the air) = 20°C
The flute is open at both ends.
<u>Required Data </u>
We are asked to determine the length of the tube.
<u>Solution</u><u> </u>
The speed of sound in air at temperature T = 20°C is found from Equation (1):
v=(331 m/s)√(1+T_C/273°C)
=342.91 m/s
The fundamental frequency of the flute is found by substituting n = 1 into Equation (2):
f=v/2L
Solve for L:
L=v/2f_1
L=0.654 m
The velocity of the ball is 12.5 m/s
Explanation:
The velocity of the ball is given by the ratio between the distance covered by the ball and the time taken:
First, we calculate the distance covered. We know that the radius of the circle is
r = 0.450 m
And the length of the circumference is
The ball makes 25.0 revolutions, so a total distance of
In a time of
t = 9.37 s
So, its velocity is
Learn more about velocity here:
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