Answer: 0.4M
Explanation:
Given that,
Amount of moles of NaOH (n) = ?
Mass of NaOH in grams = 40.0g
For molar mass of NaOH, use the atomic masses: Na = 23g; O = 16g; H = 1g
NaOH = (23g + 16g + 1g)
= 40g/mol
Since, n = mass in grams / molar mass
n = 40.0g / 40.0g/mol
n = 1 mole
Volume of NaOH solution (v) = 2.5 L
Concentration of NaOH solution (c) = ?
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
c = 1 mole / 2.5 L
c = 0.4 mol/L (Concentration in mol/L is the same as Molarity, M)
Thus, the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution is 0.4 mol/L or 0.4M
Answer:
K = 351.3
Explanation:
The relationship between the Celsius scale and kelvin scale is;
K = 273 + C
Since the Celsius temperature = 78.3
The kelvin temperature is given as;
K = 273 + 78.3
K = 351.3
The hydrogenation of ethyl cinnamate will result to an ester which can be a racemic mixture of products or just a meso compound depending on the structure of the ethyl cinnamate (cis or trans). The ester will produce a frequency of C=O stretch of <span>1750 - 1735 (s.</span>
