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3 years ago

3. Which element is most important for growing crops?

Chemistry

1 answer:

madreJ [45]3 years ago

8 0

Answer:

B. hydrogen

Explanation:

that's because hydrogen is an element.

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What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid?.

marin [14]

Answer:

What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid? The amount of acid that was added.

Explanation:

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2 years ago

Name a molecule that is small enough to enter the cell

Oksanka [162]

Answer:

oxygen molecule

Explanation:

I belive it is oxygen molecule

8 0

3 years ago

Read 2 more answers

Varvara68 [4.7K]

Answer:

Option C.

Ilegal dumping of waste

Explanation:

This is because non point source of pollution refers to source of pollution that are many and not directly one which is illegal or does not meet the legal term. This type of pollution does not have a point source, it has many sources and this type of pollution is cause by rainfall or precipitation. Where when the rain fall, it wash away the waste through to water bodies, causing pollution and endangering water bodies.

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3 years ago

How much heat is required to increase the temperature of 100.0 grams of iron from 15.0oC to 40.2oC? (The specific heat of iron i

Ksenya-84 [330]

Answer is: 1160 J of heat Is required to increase the temperature.
m(Fe) = 100 g.
∆T = 40,2 - 15 = 25,2°C.
C(Fe) = 0,46 J/g•°C.
Q = m(Fe) • C • ∆T.
Q = 100 g • 0,46 J/g•°C • 25,2°C
Q = 1160 J.
C - specific heat.

3 0

3 years ago

Read 2 more answers

A 30.0-g piece of metal at 203oC is dropped into 400.0 g of water at 25.0 oC. The water temperature rises to 29.0 oC. Calculate

oee [108]

The specific heat of the metal is 2.4733 J/g°C.

Given the following data:

Initial temperature of water = 25.0°C

Final temperature of water = 29.0°C

Mass of water = 400.0 g

Mass of metal = 30.0 g

Temperature of metal = 203.0°C

We know that the specific heat capacity of water is 4.184 J/g°C.

To find the specific heat of the metal (J/g°C):

Heat lost by metal = Heat gained by water.

$Q_{metal} = Q_{water}$

Mathematically, heat capacity or quantity of heat is given by the formula;

$Q = mc\theta$

<u>Where:</u>

Q is the heat capacity or quantity of heat.

m is the mass of an object.

c represents the specific heat capacity.

∅ represents the change in temperature.

Substituting the values into the formula, we have:

$30(203)c = 400(4.184)(29 \; -\; 20)\\\\6090c = 1673.6(9)\\\\6090c = 15062.4\\\\c = \frac{15062.4}{6090}$

Specific heat capacity of metal, c = 2.4733 J/g°C

Therefore, the specific heat of the metal is 2.4733 J/g°C.

8 0

2 years ago