The answer is D. I hope this helps
The chemical symbol for sodium bicarbonate is NaHCO₃. Its molar mass is calculated by adding the product of the molar mass of each of the component and the number of moles. That is,
molar mass of NaHCO₃ = (1 mol Na)(23 g Na/1 mol Na) + (1 mol H)(1 g H/ 1 mol H) + (1 mol C)(12 g C/1 mol C) + (3 mol O)(16 g O/1 mol O)
molar mass of NaHCO₃ = 84 g/mol
Same is to be done with sodium carbonate which has a molar mass of Na₂CO₃
molar mass of Na₂CO₃ = (2 mol Na)(23 g Na/1 mol Na) + (1 mol C)(12 g C/1 mol C) + (3 mol O)(16 g O/1 mol O)
molar mass of Na₂CO₃ = 106 g/mol
The decomposition of sodium bicarbonate to sodium carbonate is shwon below,
2NaHCO₃ --> Na₂CO₃ + H₂O + CO₂
Through conversion factors and dimensional analysis,
(1.678 g NaHCO₃)(1 mol NaHCO₃/84 g NaHCO₃)(1 mol Na₂CO₃/2 mol NaHCO₃)(106 g NaHCO₃/1 mol NaHCO₃)
= 1.06 g Na₂CO₃
<em>ANSWER: 1.06 g Na₂CO₃</em>
Answer: your answers are between d or b
Explanation:
Hello!
The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:
Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:
CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)
Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻
This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.
Have a nice day!
Answer:
though i didnt do that yet. i will google it and be right back to u.