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katen-ka-za [31]
3 years ago
11

We know that the law of conservation of energy states that energy can not be created or destroyed. It only changes form. Conside

r this energy transformation diagram. Assume that the energy input in this case is chemical potential energy and the useful energy output is kinetic energy, specifically a small fan to keep you cool. The diagram also shows how to calculate the efficiency of the fan. If the law of conservation of energy holds true, explain why the efficiency of the fan is not 100%.
A) No machine is ever 100% efficient; some energy is not transformed.
B) Some of the chemical potential energy is destroyed during the energy transformation.
C) Some of the chemical potential energy is transformed into heat energy as well as kinetic energy.
D) Conservation of energy also implies that some of the chemical potential energy is conserved or not used to run the fan.
Chemistry
2 answers:
White raven [17]3 years ago
7 0

Answer:

C) Some of the chemical potential energy is transformed into heat energy as well as kinetic energy

Explanation:

Just did it on USA Test Prep

mario62 [17]3 years ago
4 0

I'm not sure but I think the answer is C or D.

I think A is not possible because where did the energy go if it's not transformed?

B is definitely not because energy cannot be destroyed.

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Which of the following is true about two neutral atoms of the element gold?
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The charges and sizes of the ions in an ionic compound affect the strength of the electrostatic attraction holding that compound
Nadya [2.5K]

Answer:

order = SrS > SrCl2 > RbCl > CsBr

Explanation:

Comparison of the melting points of compounds is basically dependent on the charge on their cation and anion, the more the charges on the cation and anion, the stronger and greater the force of attraction and as such the melting point will be relatively higher as well.

The ionic radii is also another factor to be considered, the more the distance between ions, the lesser the bond strength and the lesser the melting point.

from the options, in terms of ionic radii SrS > SrCl2 and RbCl > CsBr

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6 0
3 years ago
For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox
ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: m_{N2}=10.682 g N_2

2) Limiting reagent: NO

3) Ammount of excess reagent: m_{N2}=4.274 g

Explanation:

<u>The reaction </u>

2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)

Moles of nitrogen monoxide

Molecular weight: M_{NO}=30 g/mol

n_{NO}=\frac{m_{NO}}{M_{NO}}

n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol

Moles of hydrogen

Molecular weight: M_{H2}=2 g/mol

n_{H2}=\frac{m_{H2}}{M_{H2}}

n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}

m_{N2}=10.682 g N_2

2) <u>Limiting reagent</u>: NO

3) <u>Ammount of excess reagent</u>:

m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}

m_{N2}=4.274 g

8 0
3 years ago
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