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4 years ago

Guys what is the answer?please help me.ASAP!

Mathematics

1 answer:

Jet001 [13]4 years ago

8 0

Cinnamon Toast Crunch is always the answer

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On the way to school, a student rides his bike to the bus stop. He then waits a few minutes for the bus to come and rides the bu

Contact [7]

Answer:

here is the sample answer

Sample Response: No, the graph is only increasing while the student rides his bike, rides the bus, and walks. It is stays the same while he waits for the bus and when the bus stops to let him off.

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4 years ago

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List five numbers that hav 3,5,and 7 as prime factors

Yuki888 [10]

15 has prime factors of 5,3
21 has prime factors of 7,3
35 has prime factors of 7,5
105 has prime factors of 7,5,3
315 has prime factors of 7,5,3,3
hope this helps

7 0

4 years ago

I need help with geometry

grandymaker [24]

Sin x = 3 / 8
sin x = 0,4
x = sin ^ -1 (0,4) = 24°
and now i gtg sorry :(

6 0

3 years ago

Read 2 more answers

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

3 years ago

HELP HELP HELP PLZ ITS DUE IN 5 MINUTES

gladu [14]

Answer:

14.58

Step-by-step explanation:

1.08 is tax multiplied by 15 is 16.20 after tax. 90% of that is 14.58

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3 years ago

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