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11111nata11111 [884]
3 years ago
14

Guys what is the answer?please help me.ASAP!

Mathematics
1 answer:
Jet001 [13]3 years ago
8 0

Cinnamon Toast Crunch is always the answer

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
26 eggs in a carton were broken. this was 5% of the total number of eggs in the carton. how many eggs were in the carton altoget
lesya692 [45]

Answer:

520 eggs

Step-by-step explanation:

5%*2 is 10%.

10%*10 is 100%,that is the full carton of eggs.

26*2*10 is 520.

There were 520 eggs in the carton altogether.

Hope this helps :)

8 0
3 years ago
Please help with #21<br><br> The length of QP = <br> The length of PR = <br> The length of QR =
Marat540 [252]
Hello!

The length of QP = 18 feet
The length of PR = 18 feet
The length of QR = 24 feet
8 0
4 years ago
What is the mean for 9, 7, 5, 9, 7, 2, 9, 7, 3, 7
MrRa [10]

Answer:

The mean is 58.7 for you

4 0
4 years ago
Read 2 more answers
A pizza delivery driver receives a bonus if she delivers a pizza to a customer in 30 minutes, plus or minus seven minutes. Write
Snezhnost [94]

Answer:

Please, see the attached file.

Step-by-step explanation:

Please, see the attached graph.

Thanks.

4 0
3 years ago
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