d is the answer
Step-by-step explanation:
all work is shown and pictured
It’s -4 and it’s -5.........
Answer:
To solve this problem, you would create two ratios and make them equal to each other, both representing laps:minute or laps/minute! With that being said, laps will be in the numerator, or on top, and minutes will be in the denominator, or the bottom! The first ratio, which we know from the problem, will be 5/8. In order to write the second ratio, we need to come up with something to put in place for what we're solving for. I like to use x. So, we need to find how many laps (x) are run in 1 minute. Remember, laps are on top and minutes are on the bottom. The second ratio would look like x/1. Then we make them equal to each other -> 5/8=x/1. You would then solve this equation by multiplying the right side of the equation by the reciprocal of the denominator! So, it would be 1/1(5/8)=x. Because then multiple the numerators and the denominators -> 1(5)=5 and 1(8)=8! This makes the equation turn into x=5/8! Because x equals the number of laps run in one minute, we can say that Ricky ran 5/8 of a lap in one minute or 0.625 laps in one minute!
Step-by-step explanation:
Answer:
7.5 L of 10% solution and 22.5 L of 30% solution
Step-by-step explanation:
Volume of 10% solution plus volume of 30% solution = total volume of 25% volume.
x + y = 30
Acid in 10% solution plus acid in 30% solution = total acid in 25% solution.
0.10 x + 0.30 y = 30 × 0.25
0.10 x + 0.30 y = 7.5
Solve the system of equations, using either substitution or elimination. I'll use substitution:
x = 30 − y
0.10 (30 − y) + 0.30 y = 7.5
3 − 0.10 y + 0.30 y = 7.5
0.20 y = 4.5
y = 22.5
x = 30 − y
x = 7.5
Sarah needs 7.5 L of 10% solution and 22.5 L of 30% solution.
Answer:
height for the building = 551.8 ft
Step-by-step explanation:
The info given describes the shape of a right triangle.
Thus:
Reference angle = Angle of elevation = 23°
Opposite side = height of the building = ?
Adjacent side = 1,300 ft
Apply trigonometric function, TOA:
Tan 23 = Opp/Adj
Tan 23 = Opp/1,300
1,300 × Tan 23 = Opp
551.817261 = Opp
Opp ≈ 551.8 ft
height for the building = 551.8 ft
