71.8 g of iron (III) oxide (Fe₂O₃) were produced from 3 moles of magnesium oxide (MgO).
Explanation:
We have the following chemical reaction:
2 FeCl₃ + 3 MgO → Fe₂O₃ + 3 MgCl₂
We see from the chemical reaction that 3 moles of magnesium oxide (MgO) will produce 1 mole of iron (III) oxide (Fe₂O₃).
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of Fe₂O₃ = 1 × 71.8 = 71.8 g
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number of moles
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A. When the substance is in its gaseous state.
<u>Explanation:</u>
When a substance is expanding against its constant volume and pressure, its temperature increases except when the substance is in gaseous state and not in liquid or solid state. So the internal energy increase in the system not only increases and maintaining the volume and pressure of the system remains constant in its gaseous phase. In the first law of Thermodynamics, it is used specifically that to especially in the case of gaseous system.
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1) Atomic radius: It increases from left to right in a period
2) Ionic radius: It increases from left to right in a period
3) First ionization energy: It increases from left to right in a period
4) Melting point: Generally decreases from left to right in a period
Answer:
15.4 g
Explanation:
The reaction that takes place is:
- 2C₅H₁₀ + 15O₂ → 10CO₂ + 10H₂O
First we <u>convert 5 grams of C₅H₁₀ into moles</u>, using its <em>molar mass</em>:
- 5 g ÷ 70 g/mol = 0.07 mol C₅H₁₀
Then we <u>convert C₅H₁₀ moles into CO₂ moles</u>, using the <em>stoichiometric coefficients</em> of the reaction:
- 0.07 mol C₅H₁₀ *
= 0.35 mol CO₂
Finally we <u>convert 0.35 moles of CO₂ into grams</u>:
- 0.35 mol CO₂ * 44 g/mol = 15.4 g
