The answer should be C.
In the website, the purpose of it is to promote the product, therfore, they will claim all the benefits, no matter it is true or not.
However, in a university study, the purpose is not to promote. They will make sure the test fair and reliable. They have the best equipments and tools and the top investigators.
Therfore, a university study is the best source.
Answer:
For the complete combustion of 10 g of glucose 11.52 g of oxygen is required.
Explanation:
Given data:
Mass of glucose = 10 g
Mass of oxygen required for complete combustion = ?
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
Now we will convert the given mass of glucose into number of moles.
Number of moles = mass/ molar mass
Number of moles = 10 g/ 180.156 g/mol
Number of moles = 0.06 mol
Now we will compare the moles of glucose with oxygen.
C₆H₁₂O₆ : O₂
1 : 6
0.06 : 6×0.06 = 0.36 mol
Mass of oxygen required:
Mass = number of moles × molar mass
Number of moles = 0.36 mol × 32 g/mol
Number of moles = 11.52 g
For the complete combustion of 10 g of glucose 11.52 g of oxygen is required.
Answer:
The speed of the given electromagnetic wave is 3 x 10⁸ m/s.
Explanation:
Electromagnetic wave is a type of energy that is commonly known as light energy. The speed of light in air is about 3 x 10⁸ meters per second (m/s).
<u>All electromagnetic waves travel at the same speed</u> which is equal to speed of light, approximately 3 x 10⁸ meters per second (m/s) through a vacuum or air.
Therefore, the speed of the given electromagnetic wave is 3 x 10⁸ m/s.
Lithium's atomic weight is 6.94 g/mol.
Need anything else?
6 ! 1ml=1cm3 (the metric systems great like that !)