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3 years ago

What scientific principles causes the different layers of the Earth?

Chemistry

1 answer:

neonofarm [45]3 years ago

7 0

Answer: Formation of the Earth's iron core.

Explanation: The stratification of Earth into its geologic layers was brought about by the formation of the Earth's iron core. The iron core was generated by a combination of radioactive decay and gravitation, which raised the temperature enough for molten iron to form.

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Ionic formula for chromuim 3 fluoride

GalinKa [24]

CrF3; Cr has a 3+ charge and F has a 1-.

3 0

3 years ago

How many significant figures are in this number? : 2.7 x 10^-3

Lady_Fox [76]

Answer:

2 significant figures i.e. 2 and 7.

Explanation:

We need to find the number of significant figures in the given number i.e. $2.7\cdot10^{-3}$ .

It has 2 significant figures i.e. 2 and 7.

It means the power of 10 doesn't count in the significant figures.

Hence, there are 2 significant figures.

6 0

3 years ago

At a certain temperature, 0.800 mol SO 3 is placed in a 1.50 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil

Elanso [62]

Answer : The value of equilibrium constant (K) is, 0.004

Explanation :

First we have to calculate the concentration of $SO_3\text{ and }O_2$

$\text{Concentration of }SO_3=\frac{\text{Moles of }SO_3}{\text{Volume of solution}}=\frac{0.800mol}{1.50L}=1.2M$

and,

$\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{0.150mol}{1.50L}=0.1M$

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

$2SO_3(g)\rightarrow 2SO_2(g)+O_2(g)$

Initial conc. 1.2 0 0

At eqm. (1.2-2x) 2x x

As we are given:

Concentration of $O_2$ at equilibrium = x = 0.1 M

The expression for equilibrium constant is:

$K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}$

Now put all the given values in this expression, we get:

$K_c=\frac{(2x)^2\times (x)}{(1.2-2x)^2}$

$K_c=\frac{(2\times 0.1)^2\times (0.1)}{(1.2-2\times 0.1)^2}$

$K_c=0.004$

Thus, the value of equilibrium constant (K) is, 0.004

3 0

4 years ago

Calculate the volume of an

yanalaym [24]

Answer:

9.0mm x 2.0mm x 2.0mm

= 18mm3

8 0

3 years ago

how many grams of fertilizer , for potassium sulfate are there in 42.3 mole of potassium sulfate? step by step

Over [174]

Answer:

The mass of 42.3 moles of potassium sulfate is 7,371.1557 grams

Explanation:

Potassium sulfate K₂SO₄ which is also known as sulphate of potash is a water soluble common component of fertilizer

The molar mass of potassium sulfate, M = 174.259 g/mol

The given number of moles of potassium sulfate, n = 42.3 moles

The mass, 'm', of a given number of moles of potassium sulfate, 'n', is given as follows;

m = n × M

Therefore, we have;

The mass, 'm', of 42.3 moles of potassium sulfate is found by plugging in the values for 'M', and 'n', in the above equation as follows;

m = 42.3 moles × 174.259 g/mol = 7,371.1557 grams

The mass of 42.3 moles of potassium sulfate, m = 7,371.1557 grams.

4 0

3 years ago