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3 years ago

Phosphorus atomic radius is smaller than magnesium atomic radius True or false

Chemistry

1 answer:

stealth61 [152]3 years ago

4 0

Answer:

True

Explanation:

Atomic radius can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).

<em>Hence, the atomic radius of phosphorus is smaller than the atomic radius of magnesium. Basically, the atomic radius of phosphorus is 98 pm while the atomic radius of magnesium is 145 pm.</em>

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Which description best characterizes the motion of particles in a solid?

antoniya [11.8K]

The particles in a solid are tightly packed and locked in place. Although we cannot see it or feel it, the particles are vibrating in place.

As these molecules heat up, they will vibrate more vigorously, and will eventually turn to water, then gas.

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3 years ago

Read 2 more answers

What is the pOH of a 0.150 M solution of potassium nitrite? (Ka HNO2 = 4.5 x 10−4 )

yanalaym [24]

Answer:

11.9 is the pOH of a 0.150 M solution of potassium nitrite.

Explanation:

Solution : Given,

Concentration (c) = 0.150 M

Acid dissociation constant = $k_a=4.5\times 10^{-4}$

The equilibrium reaction for dissociation of $HNO_2$ (weak acid) is,

$HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+$

initially conc. c 0 0

At eqm. $c(1-\alpha)$ $c\alpha$ $c\alpha$

First we have to calculate the concentration of value of dissociation constant $(\alpha )$ .

Formula used :

$k_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}$

Now put all the given values in this formula ,we get the value of dissociation constant $(\alpha )$ .

$4.5\times 10^{-4}=\frac{(0.150\alpha)(0.150\alpha)}{0.150(1-\alpha)}$

$4.5\times 10^{-4} - 4.5\times 10^{-4}\alpha =0.150\alpha ^2$

$0.150\alpha ^2+4.5\times 10^{-4}\alpha-4.5\times 10^{-4}=0$

By solving the terms, we get

$\alpha=0.0533$

No we have to calculate the concentration of hydronium ion or hydrogen ion.

$[H^+]=c\alpha=0.150\times 0.0533=0.007995 M$

Now we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.007995 M)$

$pH=2.097\approx 2.1$

pH + pOH = 14

pOH =14 -2.1 = 11.9

Therefore, the pOH of the solution is 11.9

4 0

3 years ago

Please solve for Cu,N,and O an dif you can show how cause ik confused

belka [17]

Cu⇒ 1 atom

N⇒2 atoms

O⇒6 atoms

Total 9 atoms

<h3>Further explanation </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.

A molecular formula is a formula that shows the number of atomic elements that make up a compound.

<em>(empirical formula) n = molecular formula </em>

Chemical formula : Cu(NO₃)₂

Number of Cu : 1

Number of N : 2

Number of O = 2 x 3 = 6

Total atoms in Cu(NO₃)₂ : 1 + 2 + 6 = 9

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3 years ago

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Anna007 [38]

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Explanation:

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3 years ago

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Gnoma [55]

Answer:

A. Correct

B. Wrong

C. Wrong.

D. Correct.

E. Correct.

Explanation:

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3 years ago