All categories

3 years ago

Compared to visible light, an electromagnetic wave that has a longer wavelength will also have ________.

Chemistry

1 answer:

Anestetic [448]3 years ago

6 0

Question∵

Compared to visible light, an electromagnetic wave that has a longer wavelength will also have?

Answer:

Hi, There! -Randp12- My Name Is jay I'm here to help! :)

<u><em>The correct answer is lower frequency.</em></u>

Explanation:

Information to Support My Answer :D

it is visible that wavelength and frequency follow inverse relation. For increase in wavelength, the value of frequency decreases and vice-versa.

Therefore for higher wavelength, the electromagnetic wave will also have lower frequency.

Hope this helps!

You might be interested in

(b) Which solution has a higher percent ionization of the acid, a 0.10M solution of HC2H3O2(aq) or a 0.010M solution of HC2H3O2(

boyakko [2]

Answer: The percent ionization is higher for 0.010 M solution of $HC_2H_3O_2$

Explanation:

$HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-$

cM 0M 0M

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

a) Given c= 0.10 M and $\alpha$ = ?

$K_a=1.8\times 10^{-5}$

Putting in the values we get:

$1.8\times 10^{-5}=\frac{(0.10\times \alpha)^2}{(0.10-0.10\times \alpha)}$

$(\alpha)=0.013$

$\%(\alpha)=0.013\times 100=1.3\%$

b) Given c= 0.010 M and $\alpha$ = ?

$K_a=1.8\times 10^{-5}$

Putting in the values we get:

$1.8\times 10^{-5}=\frac{(0.010\times \alpha)^2}{(0.010-0.010\times \alpha)}$

$(\alpha)=0.041$

$\%(\alpha)=0.041\times 100=4.1\%$

The percent ionization is higher for 0.010 M solution of $HC_2H_3O_2$

6 0

3 years ago

What is the total number of moles of electrons needed to produce one mole of Mg metal from MgCl2?

Murrr4er [49]

MgCl₂ = Mg²⁺ + 2Cl⁻

Mg²⁺ + 2e⁻ = Mg⁰

2 moles of electrons

8 0

2 years ago

What two states of matter are found during melting

kondaur [170]

Answer:

solid and liquid

Explanation:

6 0

3 years ago

What is the sea of instability

LiRa [457]

The "sea of instability" refers to a region of elements on the periodic table that are highly unstable. These elements have extremely short half-lives that may be measured in micro- or nanoseconds. (A nanosecond is the time it takes for light to travel one foot.) This region of unstable elements surrounds the island of stability.

6 0

3 years ago

Read 2 more answers

According to the article, HOW has the discovery of

Irina-Kira [14]

Answer:a

Explanation:

i think so cs i read the ariticle

8 0

3 years ago