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3 years ago

How do you write 308,800 in expanded form?

Mathematics

2 answers:

masya89 [10]3 years ago

8 0

Answer:

300,000 8,000 800 i think sorry if i got it wrong

Step-by-step explanation:

Anettt [7]3 years ago

8 0

Answer:

1 x 300,000 + 8 x 1,000 + 8 x 100

Step-by-step explanation:

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Write an equation of a line that passes through (-12, -14) with slope 6.

damaskus [11]

The slope intercept form of a line is y = mx + b

m = slope
b = y-intercept

Plug in the slope, 6, into m.

Rewrite the equation;

y = 6x + b
We need to find b, your y-intercept, to finish this equation.

Plug in your point coordinate, (x, y) ⇒ (-12, -14) into the equation.

-14 = 6(-12) + b

Solve for b to find the y-intercept.

-14 = -72 + b
58 = b

Your new equation (your answer) is<em> </em>y = 6x + 58.

6 0

3 years ago

what is the correct way to write three hundred nine million, fifty-eight thousand, three hundred four?

oksian1 [2.3K]

-- sitting erect, shoulders back, chest out, head up, spine straight

-- pen held loosely and comfortably in your hand

-- forearm resting lightly on the table

-- digit characters formed neatly and clearly, with uniform size and slant

<em>3 0 9, 0 5 8, 3 0 4</em> .

3 0

3 years ago

A toy rocket is lunch vertically upward from ground level in into velocity of one 28 ft./s how long will it take for the rocket

pentagon [3]

Answer:

1.14 s

Step-by-step explanation:

Time, $t=\frac {d}{s}$

Here, d is the distance and s is the speed/velocity

Since we're given the velocity, s as 28 ft/s and the distance between the position of the rocket and ground as 32 ft then

$t=\frac {32}{28}=1.142857143\approx 1.14 s$

Therefore, it needs 1.14 seconds

4 0

3 years ago

Read 2 more answers

Which of the following statements correctlydescribes the points

gregori [183]

The first statement is correct

To calculate the distance we have to substrate the values of the Y axis only since X values are constant so the distance IS 4 - - 7=4+7=11

4 0

3 years ago

Read 2 more answers

What is the simplified product of (2x)(x^2)+(2x)(x)+(2x)(-2)+(3)(x^2)+(3)(x)+(3)(-2)

NikAS [45]

(2x)(x^2)+(2x)(x)+(2x)(-2)+(3)(x^2)+(3)(x)+(3)(-2)

Simplifying

(2x)(x2) + (2x)(x) + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Remove parenthesis around (2x)

2x(x2) + (2x)(x) + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Multiply x * x2

2x3 + (2x)(x) + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Remove parenthesis around (2x)

2x3 + 2x(x) + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Multiply x * x

2x3 + 2x2 + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Remove parenthesis around (2x)

2x3 + 2x2 + 2x(-2) + (3)(x2) + (3)(x) + (3)(-2)

Reorder the terms for easier multiplication:

2x3 + 2x2 + 2 * -2x + (3)(x2) + (3)(x) + (3)(-2)

Multiply 2 * -2

2x3 + 2x2 + -4x + (3)(x2) + (3)(x) + (3)(-2)

Multiply 3 * -2

2x3 + 2x2 + -4x + 3x2 + 3x + -6

Reorder the terms:

-6 + -4x + 3x + 2x2 + 3x2 + 2x3

Combine like terms: -4x + 3x = -1x

-6 + -1x + 2x2 + 3x2 + 2x3

Combine like terms: 2x2 + 3x2 = 5x2

-6 + -1x + 5x2 + 2x3

4 0

3 years ago