(a^3-2a^2)-(3a^2-4a^3)
(a^3-2a^2)-3a^2+4a^3
5a^3-5a^2
Answer:
Step-by-step explanation:
48k+48=-3k-3
48k+45=-3k
-51k=-3
solving for k
.0588 or .059
Answer:
It would take 24 minutes for the element to decay to 50 grams
Step-by-step explanation:
The equation for the amount of the element present, after t minutes, is:

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.
Half life of 12 minutes
This means that 
So








If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?
This is t when Q(t) = 50. Q(0) = 200.








It would take 24 minutes for the element to decay to 50 grams
Answer:
Table1
-1 undefined since we cannot take the sqrt of a negative number
0 0
1 -1
4 -2
Step-by-step explanation:
f(x) = sqrt(x)
A reflection over the x axis is-f(x)
g(x) = -sqrt(x)
x -sqrt(x)
-1 undefined since we cannot take the sqrt of a negative number
0 0
1 -1
4 -2