Answer:
<em>π/2 and π/3</em>
Step-by-step explanation:
Given the equation 2cos²x - cosx = 0, to find the solution to the equation, we will follow the following step.
let P = cosx
The equation becomes 2P²-P = 0
P(2P-1) = 0
P = 0 and 2P-1 = 0
P= 0 and P = 1/2
Since P = cosx
cosx = 0 and cos(x) = 1/2
If cos(x) = 0
x = cos⁻¹0
x = 90⁰
x = π/2
If cos(x) = 1/2
x = cos⁻¹1/2
x = 60⁰
x = π/3
<em>Hence the solutions to the equation are π/2 and π/3.</em>
Answer:
sqrt(10) *x
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2
x^2 + (3x)^2 = hypotenuse ^2
x^2 + 9x^2 = hypotenuse ^2
10x^2 = hypotenuse ^2
Take the square root of each side
sqrt( 10x^2) = sqrt(hypotenuse ^2)
sqrt(10) * x = hypotenuse
Add 31 to both sides.
<span><span><span><span>3x</span>−31</span>+31</span>=<span>76+31
</span></span><span><span>3x</span>=107
</span>
Divide both sides by 3.
<span><span><span><span><span><span>3x/</span>3</span></span></span></span>=<span><span><span>107/3
</span></span></span></span><span>x=<span></span></span>
Answer:
the right answer is option D. 0.5b
I just want you know that there is another easier method