Answer:
- output = ""
- for i in range(7):
- if(i % 3 == 0):
- for i in range(5):
- output+= "*"
- output += "\n"
- else:
- for i in range(2):
- output += "* "
- output += "\n"
-
- print(output)
Explanation:
The solution code is written in Python 3.
Firstly, create a output variable that holds an empty string (Line 1).
Create an outer loop that will loop over 7 times to print seven rows of stars (Line 2). In row 0, 3 and 6 (which are divisible by 3) will accumulate up to 5 stars using an inner loop (Line 4-5) whereas the rest of the row will only print two stars with each start followed by a single space (Line 8-9) using another inner loop.
At last, print the output (Line 12).
Answer:
The Python code with the function is given below. Testing and output gives the results of certain chosen parameters for the program
Explanation:
def first_last(seq):
if(len(seq) == 0):
return ()
elif(len(seq) == 1):
return (seq[0],)
else:
return (seq[0], seq[len(seq)-1])
#Testing
print(first_last([]))
print(first_last([1]))
print(first_last([1,2,3,4,5]))
# Output
( )
( 1 , )
( 1 , 5 )
Answer:
int counter = 0;
String userInput = "";
while (userInput != "stop") {
print "What pet do you have? ";
userInput = readInputLine();
if (userInput != "stop" ){
counter = counter + 1;
print "\nYou have one ";
print userInput;
print ". Total # of Pets: ";
print counter;
}
}
Explanation:
not sure what programming language you use, therefore the answer is pseudocode but it should give you an idea how to implement a piece of code for this problem.
Also, from the way you described the exercise I'm not sure if you always are supposed to reply with "you have one" + the pet or if you should count how often the same pet was entered.
