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3 years ago

What is four fifths mines two thirds sorry for asking

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

4 0

Answer:

2/15

Step-by-step explanation:

4/5-2/3

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What is an equation of the line that passes through point (5,-8) and is parallel to the line x+y=7

Igoryamba

Answer:

The line given is equal to y=-x+7 (Through rearranging)

To find the new line, we substitute the given coordinates (5,8) in the equation without the given y-intersect (+7):

-8=-5+c

c=-3

The line parallel to x+y=7 that passes through the point (5,-8) is y=-x-3

4 0

3 years ago

If five less than y is six more than x + 1, then by how much is x less than y?

Pie

Answer:

12 more

Step-by-step explanation:

y-5= 6+ (x+1)

5+6+1=12

6 0

3 years ago

The sum of two numbers is 30.the first number is 1/5 of the second number. what are the numbers?

gizmo_the_mogwai [7]

The 2md number can be y. This makes the first number 1/5 of y

Your equation is y + 1/5y = 30
You can randomly plug in numbers and you get that the first number is 5. This means that the second number is 25

6 0

3 years ago

For the polynomial below, -2 is a zero.

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

please note -2 is not a zero ,it should be 2 is a zero.

by synthetic division

2| 1 4 -10 -4

| 2 12 4

|----------------

1 6 2 | 0

x²+6x+2=0

$x=\frac{-6 \pm \sqrt{36-8} }{2} \\or~x=\frac{-6 \pm2\sqrt{7} }{2} \\or ~x=-3\pm \sqrt{7} \\h(x)=(x-2)(x^2+6x+2)=(x-2)(x-3+\sqrt{7} )(x-3-\sqrt{7})$

7 0

3 years ago

In tennis, a first serve can be an ace, a fault, or it can be returned. In one match, a tennis player hit 24 aces, which was 25

Anastaziya [24]

Answer:

16 faults

Step-by-step explanation:

The correct question is

In tennis, a first serve can be an ace, a fault, or it can be returned. In one match, a tennis player hit 24 aces, which was 2/5 of all her first serves. If 1/3 of her first serves were returned, how many of the tennis player's first serves were faults?

Let

x -----> the number of all her first servers

y ----> the number of first services returned

z ---> the number of first services faults

we know that

The number of aces plus the number of returned plus the number of faults must be equal to the number of all her first services

$x=24+y+z$