Compare the number of x intercepts in the graph f(x)=x2 to the number of x intercepts in the graph of g(x)=x2-7. Be sure to incl ude the transformation that occurred between the parent function f(x) and its image g(x)
1 answer:
With x^2 the x-intercept is (0,0) because it meets at the origin. there are two x intercepts for g(x)=x^2-7 but only one x-int for f(x)=x^2. g(x) SHIFTED DOWN by 7 since the y-int is -7
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Step-by-step explanation:
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Solve for j(h(x)):
h(x) = x² + 4
j(x) = 4x - 1
Substitute in h(x) into "x":
j(h(x)) = 4(x² + 4) - 1
j(h(x)) = 4x² + 16 - 1
j(h(x)) = 4x² + 15
Solve at x = 2:
4(2)² + 15 = 4(4) + 15 = 31.
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