Which is the best estimate of the correlation coefficient for the scatter plot?
2 answers:
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Answer:
Option A.
Step-by-step explanation:
Consider the below figure attached with this question.
Scenario 1 represented by the graph.
From the graph it is clear that the line passes through the points (1,60) and (2,120).
Slope of the line is
The slope of line is 60. It means the speed is 60 miles per hour.
Scenario 2 defined by the equation,
If an equation defined as , then m is slope and b is y-intercept.
The slope of line is 50. It means the speed is 50 miles per hour.
The slope of Scenario 1 is greater than slope of Scenario 2. So, the Scenario 1 shows the greater speed.
Hence, the correct option is A.
Answer:
0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled
Step-by-step explanation:
To solve this question, we have to understand the normal probability distribution and the central limit theorem.
Normal probability distribution:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central limit theorem:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
In this problem, we have that:
What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?
This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So
X = 160
By the Central Limit Theorem
has a pvalue of 0.7257
X = 150
has a pvalue of 0.2743
0.7257 - 0.2743 = 0.4514
0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled
Answer:
<h2>30% is enrolled out-of-district.</h2>Step-by-step explanation:
According to the word problem, the number is increased by 50%.
To increase a number by a percent, multiply the number and the percent.
We can do this by changing both percents to decimals.
To change a percent to a decimal, divide it by 100.
The number is INCREASED by 50% so 0.5 would become 1.5.